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inessss [21]
3 years ago
5

Solve please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! |−9.8| |11 2/ 3| |−2 6/ 7|

Mathematics
1 answer:
andrezito [222]3 years ago
6 0

Answer:

|-9.8| = 9.8

|11 2/3| = 11 2/3 or 11.66

|-2 6/7| = 2 6/7 or 2.86

Step-by-step explanation:

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he ate 40 percent of the cookies

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If 3x+54+(65 × 32)+ 902- (43/12) =y, then what is y?
IceJOKER [234]

Answer:

We cannot solve without a value for x. The simplified form is 3x+\frac{36,389}{12} =y

Step-by-step explanation:

If the equation is 3x+54+(65)(32)+902-\frac{43}{12}=y then we cannot solve it until we know the value of x. We can simplify it using order of operations such as PEMDAS.

3x+54+(65)(32)+902-\frac{43}{12}=y \\3x+54+2,080+902-\frac{43}{12}=y \\3x+3,036-\frac{43}{12}=y \\3x+\frac{36,432}{12} -\frac{43}{12} =y\\3x+\frac{36,389}{12} =y

6 0
3 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


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Answer:

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Step-by-step explanation:

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What is the difference of 3.14 and the sum of 5.99 and 0.65?
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Answer:

3.5

Step-by-step explanation:

5.99+0.65=6.64

6.64-3.14=3.5

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3 years ago
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