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Murljashka [212]

3 years ago

9

A grocery store orders 47 bags of onins and 162 bags of potatoes. The onions cost 2 per bag , and potatoes cost 3 per bag How mu

ch is spent on onions and potatoes

1 answer:

Alina [70]3 years ago

7 0

Answer:

580 is spent on onions and potatoes

Step-by-step explanation:

The grocery store ordered 47 bags of onions, and 1 bag costs 2.

It also ordered 167 bags of potatoes, and the bag costs 3.

47 bags onions X 2 render 94

162 bags potatoes X 3 render 486

94 (cost of onions) + 486 (cost of potatoes) = 580

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The perimeter of two triangles are 15 and 25. The area of the smaller triangle is 36. If the triangles are similar, what is the

DanielleElmas [232]

Answer:

60

Step-by-step explanation:

Set up a ratio problem

15/25 = 36/x

15x = 900

x = 60

6 0

3 years ago

Help me solve this?

LiRa [457]

Answer:

Step-by-step explanation:

5(-5)-2=-27

5(-2)-2= -12

5(1)-2=3

5(2)-2=8

5(3)-2=13

x g(x)

-5 -27

-2 -12

1 3

2 8

3 13

5 0

3 years ago

Read 2 more answers

I need help on this please

Leya [2.2K]

The expression we have is:

$2xy\cdot xy^2$

And we are given some values for x and y:

$\begin{gathered} x=2 \\ y=4 \end{gathered}$

The first step will be to substitute the given values into the expression:

$2(2)(4)\cdot(2)(4)^2$

The next step is to solve 4^2 which is equal to 16:

$2(2)(4)\cdot(2)(16)$

And then we solve the multiplications, 2(2)(4) is equal to 16 and (2)(16) is equal to 32:

$16\cdot32$

Solving this final multiplication we get the result:

$512$

Answer: 512

8 0

1 year ago

The manager of a music store has kept records of

Marysya12 [62]

Answer:

(a) $P(x\le 3) = 0.75$

(b) $P(x\le 3) = 0.75$

<em>(b) is the same as (a)</em>

(c) $P(x \ge 5) = 0.10$

(d) $P(x = 1\ or\ 2) = 0.55$

(e) $P(x > 2) = 0.45$

Step-by-step explanation:

Given

$\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}$

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

$\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}$

This probability is calculated as:

$P(x\le 3) = P(1) + P(2) + P(3)$

This gives:

$P(x\le 3) = 0.30 + 0.25 + 0.20$

$P(x\le 3) = 0.75$

Solving (b): Probability of at most 3 CDs

Here, we consider:

$\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}$

This probability is calculated as:

$P(x\le 3) = P(1) + P(2) + P(3)$

This gives:

$P(x\le 3) = 0.30 + 0.25 + 0.20$

$P(x\le 3) = 0.75$

<em>(b) is the same as (a)</em>

<em />

Solving (c): Probability of 5 or more CDs

Here, we consider:

$\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}$

This probability is calculated as:

$P(x \ge 5) = P(5) + P(6\ or\ more)$

This gives:

$P(x\ge 5) = 0.05 + 0.05$

$P(x \ge 5) = 0.10$

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

$\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}$

This probability is calculated as:

$P(x = 1\ or\ 2) = P(1) + P(2)$

This gives:

$P(x = 1\ or\ 2) = 0.30 + 0.25$

$P(x = 1\ or\ 2) = 0.55$

Solving (e): Probability of more than 2 CDs

Here, we consider:

$\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}$

This probability is calculated as:

$P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)$

This gives:

$P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05$

$P(x > 2) = 0.45$

3 0

3 years ago

An acid is a substance that increases the concentration of H3O+ ions in solution. Look at the reaction below of phenol (C6H5OH)

Law Incorporation [45]

Answer:

The reactant that acts as an acid, by contributing an H⁺ ion to create H3O+ in the chemical equation is C₆H₅OH.

Step-by-step explanation:

According to Brønstend-Lowry, an acid is a substance that transfer a proton (hydrogen cation, H⁺) to a base, forming a base conjugate for the first and an acid conjugate for the second.

From the following reaction:

C₆H₅OH(aq) + H₂O(l) → C₆H₅O⁻(aq) + H₃O⁺(aq)

We have that the C₆H₅OH transfer a proton to the water to form its conjugate base C₆H₅O⁻ and the conjugate acid of water H₃O⁺. Hence, the C₆H₅OH is the acid and the water is the base.

Therefore, the reactant that acts as an acid, by contributing an H⁺ ion to create H3O+ in the chemical equation is C₆H₅OH.

I hope it helps you!

8 0

3 years ago

Read 2 more answers