Question

You throw a ball up into the air with an initial vertical velocity of 46 feet per second. The ball leaves your hand when it is 6 feet above the ground. After how many seconds does the ball land on the ground?

Answer 1

Answer:

after 3 seconds

Step-by-step explanation:

$h = 6 + 46t - 16t^2$

it hits the ground when h=0