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2 years ago

5

You throw a ball up into the air with an initial vertical velocity of 46 feet per second. The ball leaves your hand when it is 6

feet above the ground. After how many seconds does the ball land on the ground?

1 answer:

zepelin [54]2 years ago

6 0

Answer:

after 3 seconds

Step-by-step explanation:

$h = 6 + 46t - 16t^2$

it hits the ground when h=0

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