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2 years ago

2.86 = ? tenths + 6 hundredths =

Mathematics

2 answers:

kherson [118]2 years ago

5 0

To get 2.8 from 0.1 you have to multiply by 28. So 28 tenths. Which leaves 0.06 which is 0.01 times 6. So 6 hundredths

kondaur [170]2 years ago

4 0

2 in ones place 8 in tenths place and 6 in hundredths place

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Help please this is urgent

yulyashka [42]

Answer:

64 degrees.

Step-by-step explanation:

This is because the arrow that is not horizontal is pointing to that number.

3 0

2 years ago

An oblique cylinder has a radius of 10 meters and a volume of 2,500 cubic meters. Use Cavalieri’s Principle to solve for the hei

shusha [124]

The idea of the Cavalieri's Principle states that even if the cylinder is oblique, so long as the planes in the figure are parallel, the equation would still be equal to,
V = Bh = πr²h
Substituting,
2,500 = π(10 m)²h
h = 7.95 m
The answer should be 5 meters.

4 0

2 years ago

An observer (O) spots a plane (P) taking off from a local airport and flying at a 33° angle horizontal to her line of sight and

docker41 [41]

Answer:

the distance of the Bird (B) from the plane (P) is = 10779 ft

Step-by-step explanation:

From the given information:

a diagrammatic representation is attached below for better understanding and solution to the question.

From the diagram;

Let the Bird (B) be represent as A

The plane (P) be represented by B

The observer be represented by O

and the tower T be represented by C

we will see that:

$\overline {AB} \ \| \ \overline {OC}$

Also;

$\angle ABO = \angle BOC = 33^0$

AO = BC = 7000

Let consider the trigonometry of triangle BAO

tan θ = opposite/adjacent

tan 33° = 7000/x

0.6494 = 7000/x

x = 7000/0.6494

x = 10779.18

x = 10779 ft ( to the nearest whole number)

Thus; the distance of the Bird (B) from the plane (P) is = 10779 ft

7 0

2 years ago

If U-235 has a half-life of 713 million years and the age of the sample is 2.631 billion years old then how many half-lifes has

lutik1710 [3]

As the age of the U-235 sample is 2.631 billion years, and the half-life of U-235 is 713 million years, the sample has undergone 2.361 X 1,000,000,000 / 713 X 1,000,000 = 3.69 half lives. In each half-life the sample reduces to half its original weight according to the radioactive Half-Life Formula: ln (Nt /N0) = -kt, where N0 = mass of the original weight of radioactive material, Nt = mass of radioactive material at time t, k = decay constant and t = time interval . We have to put Nt/N0 = 1/2 for time interval = half-life.

8 0

3 years ago

Read 2 more answers

Analyze the diagram below and complete the instructions that follow. Find the area of QRS.

11Alexandr11 [23.1K]

Answer-

The area of QRS is 238.7 sq units.

Solution-

According to properties of supplementary angles,

$m\angle R+124=180\\\\m\angle Q+132=180$