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ycow [4]
3 years ago
10

Find the equation of the line with slope 2 that passes through the point (4,-8)

Mathematics
1 answer:
sesenic [268]3 years ago
3 0

Step-by-step explanation:

Given point (4 , -8) , slope (m) = 2

Now

the equation of line is

y - y1 = m ( x - x1)

y +8 = 2 ( x -4)

y + 8 = 2x - 8

2x - 8 - 8 -y = 0

2x - y - 16 = 0

which is the required equation

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What is 14 divided by 7/8
Sliva [168]

Answer:

16

Step-by-step explanation:

You have: 14 / (7/8)

To divide by fractions, all you have to do is take the reciprocal of the second number, aka flip it

so, if you do that, you get 14 * 8/7

14*8=112, and 112/7 is 16

4 0
3 years ago
Read 2 more answers
The carnival fundraiser at Westville Elementary School raised $300 on Friday. On Saturday, the carnival will raise 480 percent o
kiruha [24]

Answer:

your answer for 300+480=780 . that was on Saturday , now you have $780 the carvinal..raised 1480 .

Step-by-step explanation:

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6 0
3 years ago
Are these correct? Please help with #12
BartSMP [9]
All of them seem pretty correct.
Also the answer to 12 is this...

Remove unnecessary parentheses
-6x2/3p^8x3

Then reduce the #’s with the greatest common divisor 3

-6x2p^8

Calculate the product

-12p^8

And that’s your answer:)))





8 0
3 years ago
For integers a, b, and c, consider the linear Diophantine equation ax C by D c: Suppose integers x0 and y0 satisfy the equation;
Dmitrij [34]

Answer:

a.

x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )

b. x = -8 and y = 4

Step-by-step explanation:

This question is incomplete. I will type the complete question below before giving my solution.

For integers a, b, c, consider the linear Diophantine equation

ax+by=c

Suppose integers x0 and yo satisfy the equation; that is,

ax_0+by_0 = c

what other values

x = x_0+h and y=y_0+k

also satisfy ax + by = c? Formulate a conjecture that answers this question.

Devise some numerical examples to ground your exploration. For example, 6(-3) + 15*2 = 12.

Can you find other integers x and y such that 6x + 15y = 12?

How many other pairs of integers x and y can you find ?

Can you find infinitely many other solutions?

From the Extended Euclidean Algorithm, given any integers a and b, integers s and t can be found such that

as+bt=gcd(a,b)

the numbers s and t are not unique, but you only need one pair. Once s and t are found, since we are assuming that gcd(a,b) divides c, there exists an integer k such that gcd(a,b)k = c.

Multiplying as + bt = gcd(a,b) through by k you get

a(sk) + b(tk) = gcd(a,b)k = c

So this gives one solution, with x = sk and y = tk.

Now assuming that ax1 + by1 = c is a solution, and ax + by = c is some other solution. Taking the difference between the two, we get

a(x_1-x) + b(y_1-y)=0

Therefore,

a(x_1-x) = b(y-y_1)

This means that a divides b(y−y1), and therefore a/gcd(a,b) divides y−y1. Hence,

y = y_1+r(\frac{a}{gcd(a, b)})  for some integer r. Substituting into the equation

a(x_1-x)=rb(\frac{a}{gcd(a, b)} )\\gcd(a, b)*a(x_1-x)=rba

or

x = x_1-r(\frac{b}{gcd(a, b)} )

Thus if ax1 + by1 = c is any solution, then all solutions are of the form

x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )

In order to find all integer solutions to 6x + 15y = 12

we first use the Euclidean algorithm to find gcd(15,6); the parenthetical equation is how we will use this equality after we complete the computation.

15 = 6*2+3\\6=3*2+0

Therefore gcd(6,15) = 3. Since 3|12, the equation has integral solutions.

We then find a way of representing 3 as a linear combination of 6 and 15, using the Euclidean algorithm computation and the equalities, we have,

3 = 15-6*2

Because 4 multiplies 3 to give 12, we multiply by 4

12 = 15*4-6*8

So one solution is

x=-8 & y = 4

All other solutions will have the form

x=-8+\frac{15r}{3} = -8+5r\\y=4-\frac{6r}{3} =4-2r

where r ∈ Ζ

Hence by putting r values, we get many (x, y)

3 0
3 years ago
I was sick when my teacher taught this and now I have no clue on what to do :(
Lady bird [3.3K]
These problems are simple to solve once you know what you're looking for! All you're going to need is a protractor which is something almost every classroom has. You can also print one offline if you're currently at home. Line up the little hole in the bottom of the protractor with the point in the angle on your paper. The 0 degree line should also be matching up with the bottom angle line. Then looking at the line at the top of your angle, see to what number that line is pointing to.

https://www.google.com/search?q=protractor&source=lnms&tbm=isch&sa=X&ved=0ahUKEwiutKPf9cLTAhVm2IMKHa... 
8 0
3 years ago
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