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3 years ago

Find the equation of the line with slope 2 that passes through the point (4,-8)

Mathematics

1 answer:

sesenic [268]3 years ago

3 0

Step-by-step explanation:

Given point (4 , -8) , slope (m) = 2

Now

the equation of line is

y - y1 = m ( x - x1)

y +8 = 2 ( x -4)

y + 8 = 2x - 8

2x - 8 - 8 -y = 0

2x - y - 16 = 0

which is the required equation

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The area of a square can be found using the equation A = s², where A is the area and s is the measure of one side of the square.

noname [10]

The correct answer is B. s = √81 in. Hope I helped!

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3 years ago

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Esteban is shopping for a bookshelf. He has 58 non-fiction books and 145 fiction books. He wants each shelf to have the same num

emmasim [6.3K]

Answer:

Step-by-step explanation:

Criteria:

• same number of books on each shelf

⇒find a number that divides 58 and 145

• greatest number of books on each shelf

⇒find the greatest number that divides 58 and 145

Find the GCF of 58 and 145.

58 = 2 ⋅ 29

145 = 5 ⋅ 29The GCF of 58 and 145 is 29.

Each shelf will contain 29 books.

There are 203 total books (because 58 + 145 = 203).

Divide 203 by 29 to find the number of shelves there should be.

203 / 29 = 7

Therefore, there will be 7 shelves.

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2 years ago

What is the measure of EAB in circle F? 72° 92° 148° 200°

Arada [10]

We have been given a diagram. We are asked find the measure of arc EAB.

First of all, we will find the measure of arcs ED and CB using our given information.

We know that measure of an inscribed angle is half the measure of intercepted arc.

We can see that angle EBC is inscribed angle of arc EDC, so measure of arc EDC will be twice the measure of angle EBC.

$\widehat{EDC}=2\times m\angle EBC$

$\widehat{EDC}=2\times 80^{\circ}$

$\widehat{EDC}=160^{\circ}$

Similarly, we will find the measure of arc DCB.

$\widehat{DCB}=2\times m\angle DEB$

$\widehat{DCB}=2\times 70^{\circ}$

$\widehat{DCB}=140^{\circ}$

$\widehat{ED}=\widehat{EDC}-\wdiehat{DC}$

$\widehat{ED}=160^{\circ}-88^{\circ}$

$\widehat{ED}=72^{\circ}$

$\widehat{ED}+\widehat{DCB}+\widehat{EAB}=360^{\circ}$

$72^{\circ}+140^{\circ}+\widehat{EAB}=360^{\circ}$

$212^{\circ}+\widehat{EAB}=360^{\circ}$

$\widehat{EAB}=360^{\circ}-212^{\circ}$

$\widehat{EAB}=148^{\circ}$

Therefore, the measure of arc EAB is 148 degrees and option C is the correct choice.

8 0

3 years ago

Read 2 more answers

Radioactive Decay:

Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

Answer: The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

Step-by-step explanation:

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

$k=\frac{0.693}{t_{1/2}}$

where,

$t_{1/2}$ = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

$k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}$

The formula used to calculate the time period for a first order reaction follows:

$t=\frac{2.303}{k}\log \frac{a}{(a-x)}$

where,

k = rate constant = $0.01506days^{-1}$

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

$t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days$

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

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3 years ago

Kevin makes several cone-shaped candles. He uses a cone mold that has a height of 15 centimeters and a diameter of 10 centimeter

Natalka [10]

Answer:

1,177.5cm^3 of candle wax will be required.

Step-by-step explanation:

The attached files contain further information so please check them.

8 0

3 years ago