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3 years ago

Hijk is definitely a parallogram

Mathematics

2 answers:

Nikitich [7]3 years ago

8 0

Answer: True

Step-by-step explanation:

1. You look at the shape

2 . You just know it is

Musya8 [376]3 years ago

7 0

Answer:

Answer is TRUE.

Step-by-step explanation:

Given: HIJK is a quadrilateral.

∠KHJ = ∠IJH

we need to check if given Quadrilateral is parallelogram or not.

From symbols on side HI and JK we get, HI and JK are parallel lines.

Now we are given ,

∠KHJ = ∠IJH

For line IJ and HK with HJ as traversal, ∠KHJ = ∠IJH are alternate interior angles.

Since, Alternate Interior Angles are equal.

We have parallel line IJ and HK.

Now, Quadrilateral HIJK has two pairs of parallel opposite side.

Therefore, Answer is TRUE.

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A pool gained 10 gallons of water on Friday due to rain. How could the owner of the pool bring the water level back to its previ

Len [333]

Answer

Let her kids play in the poop and splash out 10 gallons or Drain 10 gallons of water from the pool.

Hope this helped!!

Step-by-step explanation:

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2 years ago

A card game is being played and the 4 of hearts, 8 of clubs, and 9 of hearts

Margaret [11]

B. 32.6%..............

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2 years ago

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Which is larger, 2 wholes or 9/4?

Inga [223]

answer:

9/4

step-by-step explanation:

2 as a fraction is 8/4

seeing as how 9/4>8/4

or you could convert 9/4 to a decimal which is 2.25 and 2.25>2

the larger number is 9/4

good luck :)

hopefully, this helps

have a good day !!

7 0

2 years ago

Read 2 more answers

Determine the maximized area of a rectangle that has a perimeter equal to 56m by creating and solving a quadratic equation. What

sveticcg [70]

Answer:

Area of rectangle = $196\,m^2$

Length of rectangle = 14 m

Width of rectangle = 14 m

Step-by-step explanation:

Given:

Perimeter of rectangle is 56 m

To find: the maximized area of a rectangle and the length and width

Solution:

A function $y=f(x)$ has a point of maxima at $x=x_0$ if $f''(x_0)$

Let x, y denotes length and width of the rectangle.

Perimeter of rectangle = 2( length + width )

$=2(x+y)$

Also, perimeter of rectangle is equal to 56 m.

So,

$56=2(x+y)\\x+y=28\\y=28-x$

Let A denotes area of rectangle.

A = length × width

$A=xy\\=x(28-x)\\=28x-x^2$

Differentiate with respect to x

$\frac{dA}{dx}=28-2x$

Put $\frac{dA}{dx}=0$

$28-2x=0\\2x=28\\x=14$

Also,

$\frac{d^2A}{dx^2}=-2$

At x = 14, $\frac{d^2A}{dx^2}=-2$

So, x = 14 is a point of maxima

So,

$y=28-x=28-14=14$

Area of rectangle:

$A=xy=14(14)=196\,m^2$

Length of rectangle = 14 m

Width of rectangle = 14 m

5 0

2 years ago

A fencing company charges $22per foot to install a wood fence around a rectangular pool area that is 20 feet wide and 38 feet lo

pantera1 [17]

We will need to find the perimeter here, since in this context we’re talking about fencing around a rectangular pool. The formula for perimeter is P = 2L + 2W. The L and W can stand for length/width which is the same as wide/long in this problem. I will now plug in the numbers. P = 2(38) + 2(20) which gives us 76 + 40. 76 + 40 is 116. Therefore, the perimeter is 116 ft.

I know that the fencing company charges $22 per foot. I can multiply 116 x 22 to give me $2552. The answer is $2552.

7 0

2 years ago