For the first one the nth term is 9n - 8 so the 10th term is 9x10 - 8 = 90-8 = 82
For the second one the nth term is ⅓n + ⅓ so the 11th term is ⅓x11 +⅓ = 3.9999 = 4
Answer:
- Cos 45=6/x
x=6/cos 45=6√2
x=6√2
tan 45=y/6
y=tan45 ×6
y=6
2.
sin 60=y/10
y=sin60×10
y=5√3
again
Cos 60=x/10
x=½×10
x=5
3.
Sin 45=x/5
x=1/√2×5 or
x=5√2/2
again
y=5√2/2 or 5/√2[base angle of right angled isosceles triangle]
4.
Sin 30=8/x
½×x=8
x=8*2
x=16
again
cos 30= y/x
√3/2×16=y
y=8√3
5.
sin 60=7/x
x=7/[√3/2]
x=14/√3 or 14√3/3
again
cos 60=y/x
½×14√3/3=y
7√3/2=y
y=7√3/2
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Step-by-step explanation:
-4.5x -2y = -12.5 -------(1)
3.25x -y = -0.75 --------(2)
From (2) we can make y the subject of the relation
y = 0.75+3.25x -------(3)
Input 0.75+3.25x into y in (1)
-4.5x -2(0.75+3.25x) = -12.5
-4.5x -1.5- 6.5x = -12.5
-4.5x -6.5x -1.5 = -12.5
-11x = -12.5 +1.5
-11x = -11
x = 11/11
x = 1
If x = 1,substitute 1 into x in (3)
y = 0.75+3.25x
y = 0.75 +3.25(1)
y = 0.75 +3.25
y = 4
x = 1,y = 4
Sorry I don't see a picture. But...
If they add up to 90 degrees, they are complimentary
If they add up to 180 degrees ( a straight line) they are supplementary.
If they are vertical, they will be on either side, like two v's ><