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andreev551 [17]
4 years ago
6

Select the function that defines the given sequence

Mathematics
2 answers:
evablogger [386]4 years ago
8 0

Answer:

b

Step-by-step explanation:

Vinvika [58]4 years ago
6 0

Answer:

B. F(1) = -11

F(n) = f(n-1) + 3; for n = 2,3,4...

Step-by-step explanation:

The given sequence is -11, -8, -5,-2,-1,...

The first term is f(1)=-8 and the common difference is

d =  - 8 -  - 11 = 3

The recursive definition of this sequence is given by:

f(n) = f(n - 1) + d

This implies that:

f(n) = f(n - 1) +3 \: where \: f(1) =  - 11

and n=2,3,4,5,...

The second choice is correct

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There are 3 baseball to every 5 tennis balls. How many baseballs will there need to be if there are a total of 80 tennis and bas
ser-zykov [4K]

Answer:

30 tennis balls

Step-by-step explanation:

30 to 50 is equal to 3 to 5. And if there are 30 baseballs for every 50 tennis balls, and there are 80 balls in total, well...

30+50=80

So there are 30 tennis balls

4 0
3 years ago
Y = x²+1 at x=1 what’s the solution?
ArbitrLikvidat [17]
Y = x^2 + 1
if x = 1 then
y = 1^2 + 1 ( 1^2 = 1 )
y = 1 + 1
y = 2
3 0
3 years ago
Read 2 more answers
The director of the library believes that 14% of the library's collection is checked out. If the director is right, what is the
Ksivusya [100]

Answer: 0.2643

Step-by-step explanation:

Let p be the population proportion and \hat{p} be the sample proportion .

As per given question , we have

p=0.14\\\\ \hat{p}=0.13\\\\ n=478

z-score : \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.13-0.14}{\sqrt{\dfrac{0.14(1-0.14)}{478}}}\\\\=-0.630087269176\approx-0.63

The required probability ( using z-table ):-

P(z

Hence, the probability that the proportion of books checked out in a sample of 478 books would be less than 13% = 0.2643

5 0
4 years ago
A/14=6.8<br><br><br>Please help me?
nasty-shy [4]
A=95.2
because 6.8 x 14=95.2
and 95.2/14 is 6.8
7 0
3 years ago
Read 2 more answers
1.
MA_775_DIABLO [31]
The first one simplifies to 81a^4b
Sorry, I cannot solve the second one without placement of parentheses on the exponents
7 0
3 years ago
Read 2 more answers
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