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Natalija [7]
3 years ago
13

Can you please help me with the question

Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0
180 feet

4.5 x 40 = 180
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Please show me step by step so I can learn to explain it to my son.
aleksklad [387]
These are the steps:
1. Find the area of the trapezium {Whole figure).
2. FInd the area of the rectangle (unshaded).
3. Area of the shaded = Area of trapezium - Area of the rectangle.

<u>Step 1:  Find the area of the trapezium</u>:

Formula : Area of trapezium = 1/2 (a + b)h 

Area = 1/2 ( 25 + 15) (12) = 240 yd²

<u>Step </u><u>2 :</u><u> Find the area of the rectangle</u>:

Formula : Area = Length x Width

Area = 12 x 3 = 36 yd²

<u>Step 3: Find the shaded region:</u>

240 - 36 = 204 yd²

Answer: 204 yd²

6 0
2 years ago
(19) Geometry pls help
gogolik [260]
Yes it is possible to prove this is a parallelogram.

XN = NZ means the diagonal XZ has been bisected
The same goes for diagonal WY (because NY = NW)

Furthermore, we have the pair of vertical angles XNY and ZNW which are congruent

Through SAS, we can say that triangles XNY and ZNW are congruent

Using CPCTC, we can get to the fact that angle NWZ = angle NYX which are alternate interior angles leading to proving that XY || WZ

----------------------

If you repeat those steps above, but focus on triangles WNX and YNZ, we can prove that XW || YZ

----------------------

After proving that XY || WZ and XW || YZ, this is enough to prove we have a parallelogram as the opposite sides are parallel.

3 0
3 years ago
(32 - 2) ÷ 15 + 22 I don't know how to do this
Rus_ich [418]

Answer:

its 24 hope this helps

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the equation of a line that passes through the points (-1,-5) and (-3,-4). Leave your answer in the form y=mx+c
MaRussiya [10]

Answer:

y = -1/2x - 11/2

Step-by-step explanation:

y2 - y1 / x2 - x1

-4 - (-5) / -3 - (-1)

1/ -2

= -1/2

y = -1/2x + b

-5 = -1/2(-1) + b

-5 = 1/2 + b

-11/2 = b

8 0
2 years ago
Find the number b such that the line y = b divides the region bounded by the curves x = y^2 − 1 and the y-axis into 2 regions wi
77julia77 [94]
Because of the symmetry, we can just go from x=0 to x=2 to find the area between 
<span>y = x^2 and y = 4 </span>

<span>that area = ∫4-x^2 dx from 0 to 2 </span>
<span>= [4x - (1/3)x^3] from 0 to 2 </span>
<span>= 8 - 8/3 - 0 </span>
<span>= 16/3 </span>

<span>so when y = b </span>
<span>x= √b </span>
<span>and we have the area as </span>
<span>∫(b - x^2) dx from 0 to √b </span>
<span>= [b x - (1/3)x^3] from 0 to √b </span>
<span>= b√b - (1/3)b√b - 0 </span>

<span>(2/3)b√b = 8/3 </span>
<span>b√b =4 </span>
<span>square both sides </span>
<span>b^3 = 16 </span>
<span>b = 16^(1/3) = 2 cuberoot(2) </span>
<span>or appr 2.52</span>
7 0
3 years ago
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