These are the steps:
1. Find the area of the trapezium {Whole figure).
2. FInd the area of the rectangle (unshaded).
3. Area of the shaded = Area of trapezium - Area of the rectangle.
<u>Step 1: Find the area of the trapezium</u>:
Formula : Area of trapezium = 1/2 (a + b)h
Area = 1/2 ( 25 + 15) (12) = 240 yd²
<u>Step </u><u>2 :</u><u> Find the area of the rectangle</u>:
Formula : Area = Length x Width
Area = 12 x 3 = 36 yd²
<u>Step 3: Find the shaded region:</u>
240 - 36 = 204 yd²
Answer: 204 yd²
Yes it is possible to prove this is a parallelogram.
XN = NZ means the diagonal XZ has been bisected
The same goes for diagonal WY (because NY = NW)
Furthermore, we have the pair of vertical angles XNY and ZNW which are congruent
Through SAS, we can say that triangles XNY and ZNW are congruent
Using CPCTC, we can get to the fact that angle NWZ = angle NYX which are alternate interior angles leading to proving that XY || WZ
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If you repeat those steps above, but focus on triangles WNX and YNZ, we can prove that XW || YZ
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After proving that XY || WZ and XW || YZ, this is enough to prove we have a parallelogram as the opposite sides are parallel.
Answer:
its 24 hope this helps
Step-by-step explanation:
Answer:
y = -1/2x - 11/2
Step-by-step explanation:
y2 - y1 / x2 - x1
-4 - (-5) / -3 - (-1)
1/ -2
= -1/2
y = -1/2x + b
-5 = -1/2(-1) + b
-5 = 1/2 + b
-11/2 = b
Because of the symmetry, we can just go from x=0 to x=2 to find the area between
<span>y = x^2 and y = 4 </span>
<span>that area = ∫4-x^2 dx from 0 to 2 </span>
<span>= [4x - (1/3)x^3] from 0 to 2 </span>
<span>= 8 - 8/3 - 0 </span>
<span>= 16/3 </span>
<span>so when y = b </span>
<span>x= √b </span>
<span>and we have the area as </span>
<span>∫(b - x^2) dx from 0 to √b </span>
<span>= [b x - (1/3)x^3] from 0 to √b </span>
<span>= b√b - (1/3)b√b - 0 </span>
<span>(2/3)b√b = 8/3 </span>
<span>b√b =4 </span>
<span>square both sides </span>
<span>b^3 = 16 </span>
<span>b = 16^(1/3) = 2 cuberoot(2) </span>
<span>or appr 2.52</span>
