To prove a similarity of a triangle, we use angles or sides.
In this case we use angles to prove
∠ACB = ∠AED (Corresponding ∠s)
∠AED = ∠FDE (Alternate ∠s)
∠ABC = ∠ADE (Corresponding ∠s)
∠ADE = ∠FED (Alternate ∠s)
∠BAC = ∠EFD (sum of ∠s in a triangle)
Now we know the similarity in the triangles.
But it is necessary to write the similar triangle according to how the question ask.
The question asks " ∆ABC is similar to ∆____. " So we find ∠ABC in the prove.
∠ABC corressponds to ∠FED as stated above.
∴ ∆ABC is similar to ∆FED
Similarly, if the question asks " ∆ACB is similar to ∆____. "
We answer as ∆ACB is similar to ∆FDE.
Answer is ∆ABC is similar to ∆FED.
Answer:
f = l + -2lx-1 + 3x-1
Step-by-step explanation:
15, 28, 41.
add the common difference to each consecutive term to find the next term in the sequence.
2+ 13= 15
15+ 13= 28
28+ 13= 41
Answer:
x + 65 <u>< </u>108
Step-by-step explanation:
Answer:
y = -3/4x - 6
Step-by-step explanation:
Use y-intercept (0, -6) and slope -3/4 and put into y=mx+b form to solve for b
Remember that m is also known as slope!
-6=(-3/4 * 0) + b
b= -6
y= -3/4x - 6
