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3 years ago

Mr. Lim read 10 pages. Mr Smith read 15 pages. How many did Mr. Want read?

Mathematics

2 answers:

vazorg [7]3 years ago

6 0

It doesn't say anything about him.

Usimov [2.4K]3 years ago

5 0

Answer:

Mr. Want read nothing

Step-by-step explanation:

Tricky question. Here it's not a mathematical problem but it's a grammatical problem.Mr. Want is a person and that is denoted by the first capital letter and the question pattern as well.

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It is known that the mass, m(t), of a radio-active substance decreases as it decays, and that the equation governing this is m′(

Murljashka [212]

Answer:

m(t) = m₀ e⁻⁰•⁰¹⁵ᵗ

Half-Life = 46.21 years.

Step-by-step explanation:

Radioactive reactions always follow a first order reaction dynamic

Let the initial mass of radioactive substance be m₀ and the mass at any time be m

(dm/dt) = -Km (Minus sign because it's a rate of reduction)

The question provides K = 0.015 from the given differential equation

(dm/dt) = -0.015m

(dm/m) = -0.015dt

∫ (dm/m) = -0.015 ∫ dt

Solving the two sides as definite integrals by integrating the left hand side from m₀ to m and the Right hand side from 0 to t.

We obtain

In (m/m₀) = -0.015t

(m/m₀) = (e^(-0.015t))

m = m₀ e^(-0.015t)) = m₀ e⁻⁰•⁰¹⁵ᵗ

m(t) = m₀ e⁻⁰•⁰¹⁵ᵗ

At half life, m(t) = (m₀/2), t = T(1/2)

(m₀/2) = = m₀ e⁻⁰•⁰¹⁵ᵗ

e⁻⁰•⁰¹⁵ᵗ = (1/2)

In e⁻⁰•⁰¹⁵ᵗ = In (1/2)

-0.015t = - In 2

t = (In 2)/0.015

t = (0.693/0.015)

t = 46.21 years

Half life = T(1/2) = t = 46.21 years.

Hope this Helps!!!

7 0

3 years ago

The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea

anyanavicka [17]

Hello !
If you mist find the area of the rhombus,you need to calculate the length of the diagonals.

We have the rhombus ABCD.The diagonals are are AC and BD .
<span>Here's a formula to find out the distance between two points in the Cartesian system : (let's take randomly 2 point and their coordinates)
</span>
<span> M (m₁,m₂) ; N (n₁,n₂) ⇒ MN = \sqrt{ (m_{1} - n_{1})^{2} + (m_{2} - n_{2})^{2} }
</span>

Now it's simple to calculate the diagonals :

$AC = \sqrt{ (-4-6)^{2} +(-2-8)^{2}} \\ \\ AC= \sqrt{ (-10)^{2} + (-10)^{2} } \\\\AC = \sqrt{ 100+100} \\\\ AC =\sqrt{ 200 } \\\\AC=10 \sqrt{2} \\ \\ \\ BD = \sqrt{ (-2-4)^{2} + 6^{2} } \\\\BD=\sqrt{ (-6)^{2} + 6^{2} }\\\\BD= \sqrt{6^{2}+6^{2}} \\\\BD= \sqrt{36+36} \\\\BD= \sqrt{72} \\\\BD=6 \sqrt{2}$

The area is : $\frac{AC*BD}{2} = \frac{ 10\sqrt{2} * 6\sqrt{2} }{2} = \frac{60*2}{2} =60$

Answer: 60 u²

The representation is below.
Have a nice day :)

3 0

3 years ago

Read 2 more answers

Help this is due today!!!!!!!

oee [108]

The answer I believe is 5 because 2 vases hold 10 red roses and 5 yellow roses. But since the person has 3 vases but it has to be the same amount as the first person. They would both have 30 flowers in their vases. But then each of the vases has 6 red roses so you just do 30 divided by 6 and you get 5.

4 0

3 years ago

If 4 cooks can prepare a buffet in 15 mins how long would it take 6 cooks

mixas84 [53]

Answer:

it will probably take the same amount of time since they are cooking the same amount and the food doesn't take any less to cook if there's more people but they could tidy and bring the food out faster but the time to cook the food will remain the same.

5 0

3 years ago

(-3 1/2)-(-4 1/4)= -7/2-(-17/4) equals what

solniwko [45]

Answer:

3/4=3/4

Step-by-step explanation:

8 0

3 years ago