What is the domain of the function..... {TIMED PLS HURRY}

Mathematics

1 answer:

timofeeve [1]2 years ago

6 0

try c im sorry if im wrong i tried

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Enter a formula in cell B3 using the Vlookup function to find the meaning for thr medical abbrevation listed in cell A3. use the

NeX [460]

Formulas tab > in the Function Library group, click Lookup & Reference button, select VLOOKUP. Type A3 in the Lookup_value argument box. Type Abbreviation in the Table_array argument box. Type 2 in the Col_num argument box. Type False in the Rang_lookup box. Click OK, is this what you were looking for?

8 0

2 years ago

Use the quadratic formula to solve the<br> quadratic equation. SHOW ALL WORK.<br> 2 −8+41 = 0

horsena [70]

Answer:

Solving the equation $x^2-8x+41=0$ using quadratic formula we get $x=4+5i \ or \ x=4-5i$

Step-by-step explanation:

We need to solve the equation $x^2-8x+41=0$ using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a=1, b=-8 and c=41

Putting values in formula and finding x

$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i$

So, Solving the equation $x^2-8x+41=0$ using quadratic formula we get $x=4+5i \ or \ x=4-5i$

5 0

2 years ago

Plz help me with this question thanks

Verizon [17]

Answer:

Step-by-step explanation:

7 0

2 years ago

An experiment consists of tossing a coin and drawing a card, with the card-drawing stage dependent on the result of the coin tos

belka [17]

Well .5 for coin toss and with 52 cards in deck and clubs and spades makes it 26 so its 1/26 then those are your probabilities.<span>
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3 0

2 years ago

Read 2 more answers

Graph f(x)=-2x^2-12x-21

ELEN [110]

Step-by-step explanation:

First, find the vertex. The x coordinate is -b/2a, or 12/-4=-3. Plug this back in to get -18+36-21 or -3, so the vertex is (-3, -3). Now, slowly make the x -2, -1, 0, 1, on and on. Because parabolas are symmetric along the vertex, they will have the same values as -4, -5, -6, on and on.

5 0

2 years ago