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3 years ago

Help me please this is due in 10 minutes, please help !!!

Mathematics

1 answer:

fredd [130]3 years ago

6 0

Answer:

Step-by-step explanation:

the answer is d

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A+1=1 find the value of b^a

Ray Of Light [21]

Answer:

Step-by-step explanation:

a+1=1

a=1-1

a=0

b^a which means:

b^0

whenever power is 0 answer is always one

so value of b^a is 1

6 0

3 years ago

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Plss help with this ill give branliest to whoever

vampirchik [111]

Answer:

Step-by-step explanation:

HAHAHA

THE PERSON ABOVE ME

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3 years ago

Pls answer this question!!!

Radda [10]

Answer:

The answer is step 1.

Step-by-step explanation:

Because 1/4 times 1/3k would be 1/12k.

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3 years ago

Which values of a, b, and c correctly complete the division?

Naily [24]

$\bf \cfrac{a}{b}\div\cfrac{c}{d}\implies \cfrac{a}{b}\cdot \cfrac{ d}{c}\impliedby \qquad therefore\qquad \implies \cfrac{1}{4}\div \cfrac{5}{6}=\cfrac{1}{\underline{4}}\cdot \cfrac{\underline{6}}{\underline{5}}$

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3 years ago

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Use f’( x ) = lim With h ---> 0 [f( x + h ) - f ( x )]/h to find the derivative at x for the given function. 5-x²

beks73 [17]

<h2>Answer:</h2>

The derivative of the function f(x) is:

$f'(x)=-2x$

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

$f(x)=5-x^2$

We have:

$f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)$

( Since,

$(a+b)^2=a^2+b^2+2ab$ )

Hence, we get:

$f(x+h)=5-x^2-h^2-2xh$

Also, by using the definition of f'(x) i.e.

$f'(x)= \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}$

Hence, on putting the value in the formula:

$f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x$

Hence, the derivative of the function f(x) is:

$f'(x)=-2x$

3 0

3 years ago

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