3) The sum of three consecutive numbers is 72. What are the smallest of these numbers?
1 answer:
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We can solve this by using the P<span>ythagorean theorem which is below:
Or we can say
</span>
<span>w = widht
h = height
d = diagonal measure
With that said, we know the height is .75 times the width so .75w. We also know d = 34, which is our diagonal measure.
w = don't know yet but need to find
h = .75w
d = 34
Now lets plugin the information we know into our equation
</span>
Now lets to the math
Combine like terms
Divide both sides of the equal sign by 1.5625
Now take the square root on both sides of the equal sign
So the width is 27.2
We can check this by putting 27.2 back into our original equation
Or we can say
</span>
<span>w = widht
h = height
d = diagonal measure
With that said, we know the height is .75 times the width so .75w. We also know d = 34, which is our diagonal measure.
w = don't know yet but need to find
h = .75w
d = 34
Now lets plugin the information we know into our equation
</span>
Now lets to the math
Combine like terms
Divide both sides of the equal sign by 1.5625
Now take the square root on both sides of the equal sign
So the width is 27.2
We can check this by putting 27.2 back into our original equation
Answer:
Step-by-step explanation:
Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).
The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.
We identify the coefficients for the like terms, it comes
a = -2 and 16a = -32 (which is equivalent). So, we can write in .
The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.
And we can write in
Hope this helps.
Do not hesitate if you need further explanation.
Thank you