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Flura [38]
3 years ago
11

Pete's Deli sells corned beef at $2.55 per pound. It pays its wholesaler $1.95 per pound. What is the markup rate based on A) co

st and B) selling price? (Round to nearest tenth percent.)
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
4 0

Answer:

Step-by-step explanation:

Given

Selling price S.P.=\$ 2.55

Cost price C.P.=\$ 1.95

we know marked up price is

C.P.+markup=S.P.

Markup=2.55-1.95=\$ 0.6

So markup according to cost price

\Rightarrow \frac{0.6}{1.95}\times 100=30.76\ \%

Markup according to the selling price

\Rightarrow \frac{0.6}{2.55}\times 100=23.52\ \%

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kvasek [131]

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For example:

(x^{2} )^{3} = x^6

(x^{3} )^5=x^{15}


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3})=x^{5}

(x^{1} )(x^{2})=x^{3}


(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}

You multiply 3 into each exponent in the numerator and the denominator

\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}


When you have something like this:

\frac{x^{2}}{x^5}

You subtract the exponents together, so:

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Your answer is the second option

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A study in your town found that 54 in 1,762 people have a post office box what percent of the people in town have a post office
gavmur [86]
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Step-by-step explanation:

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Step-by-step explanation:

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Please help with the question attached. I really need help! Thanks!
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