The equation of a line that goes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so, given the point (-2,8)
x1=-2
y1=8
y-8=m(x-(-2))
y-8=m(x+2)
the equation is y-8=m(x+2) where m is the slope
or you could rewrite it to get y=mx+2m+8
Answer:
Step-by-step explanation:
Given that minimum is 8 and maximum equals 82
Range = 
No of classes =6
Class width = 76/6 ~13
But not given whether variable is discrete or continuous.
If discrete, we have classes as
8-20, 21-33, 34-46, 47-59, 60-72, 73-85
If continuous, we have classes as
8 to <21
21 to <34
and ... ending 73-<86
Answer:
1.2
Step-by-step explanation:
because its m=not whol e
Vas happenin!
Hope your day is going well
I think it’s A
Sorry if it’s wrong
Hope this helps *smiles*
Answer:
B
Step-by-step explanation: