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Lera25 [3.4K]
2 years ago
7

Joe does push-ups, sit-ups, and jumping jacks. He does these in a different order every day. How many different orders are possi

ble?
Mathematics
2 answers:
oksano4ka [1.4K]2 years ago
5 0
He could do all three exercises in 6 different orders
Ex. 
123
132
213
231
312
321

Hope this helps! :3
aivan3 [116]2 years ago
3 0
There are six different orders
p, s, j
p, j, s
s, j, p
s, p, j
j, p, s
j, s, p
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Step-by-step explanation:

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3 years ago
Please help! Mathematics
weeeeeb [17]

Answer:

y = 2

Step-by-step explanation:

Kindly view the attached image to see the rules when looking for the horizontal asymptote.

In this situation we have 2x² / x²

The powers of both are equal to each other therefore the horizontal asymptote will be at the coefficient of the numerator divided by the coefficient of the denominator.

In other words the horizontal asymptote is at y = 2/1 or just 2

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2 years ago
Integrate sin^-1(x) dx<br><br> please explain how to do it aswell ...?
Lynna [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2264253

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx\qquad\quad\checkmark}


Trigonometric substitution:

\mathsf{\theta=sin^{-1}(x)\qquad\qquad\dfrac{\pi}{2}\le \theta\le \dfrac{\pi}{2}}


then,

\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}


So the integral \mathsf{(ii)} becomes

\mathsf{=\displaystyle\int\! \theta\,cos\,\theta\,d\theta\qquad\quad(ii)}


Integrate \mathsf{(ii)} by parts:

\begin{array}{lcl} \mathsf{u=\theta}&\quad\Rightarrow\quad&\mathsf{du=d\theta}\\\\ \mathsf{dv=cos\,\theta\,d\theta}&\quad\Leftarrow\quad&\mathsf{v=sin\,\theta} \end{array}\\\\\\\\ \mathsf{\displaystyle\int\!u\,dv=u\cdot v-\int\!v\,du}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-\int\!sin\,\theta\,d\theta}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-(-cos\,\theta)+C}

\mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta+cos\,\theta+C}


Substitute back for the variable x, and you get

\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=sin^{-1}(x)\cdot x+\sqrt{1-x^2}+C}\\\\\\\\ \therefore~~\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=x\cdot\,sin^{-1}(x)+\sqrt{1-x^2}+C\qquad\quad\checkmark}


I hope this helps. =)


Tags:  <em>integral inverse sine function angle arcsin sine sin trigonometric trig substitution differential integral calculus</em>

6 0
3 years ago
What is the factored form of x^3-1
Lena [83]
X^3-1 rewrite as x^3-1^3
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a=x, b=1
(x-1)(x^2+x*1+1^2)
(x-1)(x^2+x+1)
5 0
3 years ago
Read 2 more answers
1+1=? HHHHHHELP!!!!!!!
nadezda [96]

Answer:

2,thanks,for the points

7 0
2 years ago
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