Answer:
Jenna had 25 quarters and 15 dimes.
Step-by-step explanation:
Let Q = the number of quarters and D = the number of dimes.
Then:
1) Q+D = 40 "One week she had 40 coins, all of them dimes and quarters...."
2) 0.25Q+0.1D = $7.75 "...she had a total of $7.75."
Rewrite equation 1) as: D = 40-Q and substitute into equation 2).
2a) 0.25Q+0.1(40-Q) = 7.75 Simplify the left side.
2b) 0.25Q+4-0.1Q = $7.75 Subtract 4 from both sides.
2c) 0.25Q-0.1Q = 3.75 Combine the like-terms on the left side.
2d) 0.15Q = 7.75 Divide both sides by 0.15
2e) Q = 25 and:
D = 40-Q
D = 40-25
D = 15
Jenna had 25 quarters and 15 dimes.
-8 - 5n = 64 + 3n
+5n +5n add 5n to both sides, 5n's cancel out on the left.
______________
-8 = 64 + 8n
-64 -64 subtract 64 on both sides, 64's cancel out on the right.
______________
-72 = 8n
___ ___ divide 8 on both sides, 8's cancel out from the right.
8 8
n= -9, final answer
Answer:
Find the value of x:-
To find Y, use Pythagorean theorem:- 




subtract 1.96 from both sides


Now, to find x:-



<u>~OAmalOHopeO</u>
You would multiply 4 by 72 then u multiply 4 * -6 then after that you would add 15
Answer:
infinite solutions
Step-by-step explanation:
Eliminate parentheses and collect terms:
3x -12 +5 -x = 2x -7
2x -7 = 2x -7
This is true for any value of x. There are an infinite number of solutions.