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3 years ago

Find the length of side AB.Give your answer to 3 significant figures.HELP NEEDED!

Mathematics

1 answer:

Vladimir [108]3 years ago

8 0

Step-by-step explanation:

solve the equation with formula : SOH, CAH,TOA.

from the above, SOH is to be used to answer the question.

so, Sin∆=Opp/Hyp

∆=41°

Opposite=AB

Hyp= 13.5cm

sin 41°=AB/13.5

sin41°=0.6560

0.6560= AB/13.5

AB=13.5*0.6560

AB=8.856cm

to three significant figure AB=8.86 cm approximately

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What is 1 tenth of 3.0. as a decimal

tangare [24]

Answer=0.3

1/10 of 3.0 is 0.3

3.0*(1/10)=0.3

4 0

3 years ago

A hardware store owner is replenishing his stock of base paint for an upcoming home improvement sale. He conducted a survey to d

antiseptic1488 [7]

Solution:

Matte Satin Glossy Total

Homeowners 0.08 0.20 0.24 0.52

Contractors 0.04 0.26 0.18 0.48

Total 0.12 0.46 0.42 1

Approximately what percentage of contractors prefer the glossy finish?

Answer: Percentage of contractors who prefer the glossy finish is:

$\frac{0.18}{0.48}=0.375
$ or $37.5\%$

Therefore, the option D. 37.5% is correct

6 0

3 years ago

Read 2 more answers

Integrate sin²2x cos²2x dx

DochEvi [55]

$\sin^2x=\dfrac{1-\cos2x}2$
$\cos^2x=\dfrac{1+\cos2x}2$

From the identities above, you have

$\sin^22x\cos^22x=\dfrac{(1-\cos4x)(1+\cos4x)}4=\dfrac{1-\cos^24x}4$

Applying once more, you have

$\dfrac{1-\cos^24x}4=\dfrac{1-\dfrac{1+\cos8x}2}4=\dfrac{1-\cos8x}8$

So,

$\displaystyle\int\sin^22x\cos^22x\,\mathrm dx=\frac18\int(1-\cos8x)\,\mathrm dx=\frac x8-\frac1{64}\sin8x+C$

7 0

3 years ago

Find sin(2x), cos(2x) and tan (2x) from the given information. cot(x)=2/3, x in quadrant I

Usimov [2.4K]

Answer:

1.) 6√13/13

2.) 4√13/13

3.) 3

Step-by-step explanation:

given that cot(x) = 2/3

But cot(x) = 1/tan(x)

Substitutes 1/tan(x) for cot(x)

1/tan(x) = 2/3

Reciprocate both sides

Tan(x) = 3/2 = opposite/adjacent

Use pythagorean theorem to find the hypothenus.

Hypothenus = sqrt ( 3^2 + 2^2 )

Hypothenus = sqrt ( 9 + 4 )

Hypothenus = sqrt (13)

Hypothenus = √13

1.) Sin(x) = opposite/hypothenus = 3/√13

Rationalise

3/√13 × √13/√13

3√13/13

Sin(2x) = 2 × 3√13/13

Sin(2x) = 6√13/13

2.) Cos( x ) = adjacent/hypothenus

Cos (x) = 2/√13

Rationalise

2/√13 × √13 /√13

2√13/13

Cos(2x) = 2 × 2√13/13

Cos(2x) = 4√13/13

3.) Tan (x) = 3/2

tan (2x) = 2 × 3/2

Tan(2x) = 3

4 0

3 years ago

The coordinates of parallelogram UVWZ are U(a, 0), W(c - a, b), and Z(c, 0). Find the coordinates of V without using any new var

UkoKoshka [18]

Check the picture below.

so, as you can see, the UV segment is parallel to ZW, and therefore, they're the same slope, hmmm wait just a second, what is the slope of ZW anyway?

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&Z&(~ c &,& 0~) 
% (c,d)
&W&(~ c-a &,& b~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{b-0}{(c-a)-c}\implies \cfrac{b}{-a}$

since now we know the ZW slope, we also know what is the slope for UV, thus,

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&U&(~ a &,& 0~) 
% (c,d)
&V&(~ x &,& y~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{y-0}{x-a}~~=~~\stackrel{ZW's~slope}{\cfrac{b}{-a}}
\\\\\\
\begin{cases}
y-0=b\implies \boxed{y=b}\\
-----------\\
x-a=-a\implies \boxed{x=0}
\end{cases}\qquad \qquad V~(0,b)$

8 0

3 years ago