If a line perpendicular to 2y=x+5 that passes through (2,1) using the slope- intercept form

1 answer:

4 0

Slope of 2y = x + 5:-
This is y = 0.5 x + 2.5 in slope intercept form so its slope = 0.5

Slope of the line perpendicular to it = -1 / 0.5 = -2

it passes through (2 , 1) so we have

y- 1 = -2(x - 2)
y = -2x + 4 + 1

The answer is y = -2x + 5

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Step-by-step explanation:

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Formula for calculating the the test:

t = [ (x₁ - x₂) - d ] / sqrt[(s₁²/n₁) + (s₂²/n₂)]

where x₁ = 37.6, x₂ = 39.3, d = 0 assuming equality = 37.6 - 39.3 = -1.7

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P value:

Lets find the degree of freedom:

DF = (s₁²/n₁ + s₂²/n₂)² / { [ (s₁² / n₁)² / (n₁ - 1) ] + [ (s₂² / n₂)² / (n₂ - 1) ] }

DF = (24.01/50 + 7.29/58)² / {[(24.01 / 50)² / 50-1)] + (7.29/58)² / 58-1)]}

DF = (0.4802 + 0.1257)² /{[ (0.4802)²/49] + (0.1257)²/57)]}

DF = (0.6059)²/ (0.00471 + 0.00028)

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I would use a calculator to solve this.

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