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Likurg_2 [28]
3 years ago
7

If a line perpendicular to 2y=x+5 that passes through (2,1) using the slope- intercept form

Mathematics
1 answer:
arlik [135]3 years ago
4 0
Slope of  2y = x + 5:-
This is y = 0.5 x + 2.5  in slope intercept form so its slope = 0.5

Slope of the line perpendicular to it = -1 / 0.5 = -2

it passes through (2 , 1) so we have

y- 1 = -2(x - 2)
y = -2x + 4 + 1

The answer is y = -2x + 5

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If on the unit circle C, the distance from P(1, 0) to the point T ( 4/5 , 3/5 ) is x, determine the coordinates of the point at
AveGali [126]

Answer:

(\frac{4}{5}, -\frac{3}{5}  )

Step-by-step explanation:

The point P(1,0) and T(\frac{4}{5}, \frac{3}{5}  ) are on the unit circle C and the arc length from P to T is x.

Let us assume that point P - x i.e. the point obtained by moving clock wise direction along the circle from P is T'.

Because of the symmetry of the circle about the coordinate axes, the x-coordinate of point T' will be \frac{4}{5} and the y-coordinate will be -\frac{3}{5}.

So, coordinates of T' are (\frac{4}{5}, -\frac{3}{5}  ).

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3 years ago
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8 0
4 years ago
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nadezda [96]

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3 years ago
Please solve for M&lt;QTR​
Andru [333]

Answer:

m∠QTR = 98°

Step-by-step explanation:

From the picture attached,

Radii of the circle are TQ and TR measuring equal lengths.

Therefore, ΔTQR is a isosceles triangle.

Opposite angles of the equal sides will be equal in measure.

m∠RQT = m∠TRQ = 41°

By angle sum theorem,

m∠RQT + m∠TRQ + m∠QTR = 180°

41° + 41° + m∠QTR = 180°

m∠QTR = 180° - 82°

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Therefore, m∠QTR = 98°

7 0
3 years ago
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