Answer:
[2P-3.) ^2+(2P+3)^2[2P-3.) ^2+(2P+3)^2[2P-3.) ^2+(2P+3)^2
Answer:
A).Amount = $218250
B). Amount = $88700
Step-by-step explanation:
A) .$5000 in an account at age 23, and withdraw it 42 years
Number of years t= 42 years
Principal P = $5000
Rate r= 9%
Number of times compounded n= 42
A= p(1+r/n)^(nt)
A= 5000(1+0.09/42)^(42*42)
A= 5000(1+0.002143)^(1764)
A= 5000(1.002143)^1764
A= 5000(43.65)
A= 218250
Amount = $218250
B).waits 10 years before making the deposit, so that it stays in the account for only 32 years
Number of years t= 32 years
Principal P = $5000
Rate r= 9%
Number of times compounded n= 32
A= p(1+r/n)^(nt)
A= 5000(1+0.09/32)^(32*32)
A= A= 5000(1+0.0028125)^(1024)
A= 5000(1.0028125)^1024
A= 5000(17.74)
A= 88700
Amount = $88700
Unfortunately, you haven't shared the "figure below" that shows the dimensions of this parcel of land. Without being able to calculate the area of the parcel, you cannot really answer this question exactly.
Suppose that the area of the parcel were 6000 square meters. Dividing that by 1500 square meters, we get 4, which represents the number of zebras that can live on this (example) parcel.
Figure out the area of your parcel, in square meters, and thend divide your result by 1500 square meters. This will give your your answer. Please note: your answer will be a COUNT of zebras. "meters" does not belong in this answer.
