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Svet_ta [14]
4 years ago
10

Solve for x in terms of p

Mathematics
1 answer:
zloy xaker [14]4 years ago
7 0
You cross multiply and you get: p= 5/9x
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There are 64 animals at the zoo. ⅜ of the animals are birds. How many birds are at the zoo?
xxTIMURxx [149]

Answer:

24

Step-by-step explanation:

3/8 of the 64 total animals at the zoo are birds.

To solve, this, multiply 3/8 and 64

3/8*64=24

Another way to solve would be to make a proportion

3/8=x/64

Multiply both sides by 64 to get x by itself

64(3/8)=(x/64)64

24=x

So, 24 out of the 64 animals are birds

5 0
4 years ago
Read 2 more answers
The sum of three consecutive integers is -75.
rusak2 [61]

Answer:

Suppose 3 consecutive integers are X-1,X,X+1

Step-by-step explanation:

Sum = X-1+X+X+1= -78

            3X=-78

             X= -78/3

             X= -26

3 consecutive integers are, -27, -26,-25.

smallest integer is -27

8 0
3 years ago
How many 9's are in 99
MrRissso [65]

Answer:

11 or 2

Step-by-step explanation:

11: You take 99/9 to see how many times 9 could go into 99, which would be 11.

2: You just look at the number and you see that there are 2 9s in 99.

-I hope this helps!-

-I didn't know which answer you were looking for so I put both!-

-Please mark as brainliest!-

-Good luck!-

4 0
3 years ago
Please solve number 11:(​
MrRa [10]

Answer:

Market price $400

Cost price $300

Step-by-step explanation:

MP: market price

CP: cost price

1. (MP x 0.9) - CP = 60

CP = 0.9MP - 60

2. MP - CP = 100

CP = MP - 100

0.9MP - 60 = MP - 100

MP - 0.9MP = 100 - 60

0.1MP = 40

MP = 400

Cost price = MP - 100 = 400 - 100 = 300

3 0
2 years ago
1. Let x[n] be a signal with x[n] = 0 for n<-1 and n > 3. For each signal given below, determine the values of n for which
valentina_108 [34]

Answer:

a) n<1 and n>5

b)  0 < n < -4

c)  n > 2 and n < -2

Step-by-step explanation:

The signal is given by x[n] = 0 for n < -1 and n > 3

The problem asks us to determine the values of n for which it's guaranteed to be zero.

a) x[n-2]

We know that n -2 must be less than -1 or greater than 3.

Therefore we're going to write down our inequalities and solve for n

n-2

Therefore for n<1 and n>5 x [n-2] will be zero

b) x [n+ 3]

Similarly, n + 3 must be less than -1 or greater than 3

n+30

Therefore for n< -4 and n>0, in other words, for 0 < n < -4  x[n-2] will be zero

c)x [-n + 1]

Similarly, -n+1 must be less than -1 or greater than 3

-n+13-1\\-n>2\\n

Therefore, for n > 2 and n < -2  x[-n+1] will be zero

4 0
4 years ago
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