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2 years ago

You spinner that has 12 equal sides sections number 1 through 12 find each probability probability three or four

Mathematics

1 answer:

grigory [225]2 years ago

4 0

Answer:

1 in 12 chance of landing on 3

1 in 12 chance of landing on 4

1 in 6 chance of landing on either 3 or 4

Step-by-step explanation:

12 equal sections means probability is 1 in 12 of landing on any one numbered section.

2 in 12 or 1 in 6 chance of landing on either of two numbered sections in one attempt.

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What is the solution to the equation shown below

sattari [20]

$y=\dfrac{3}{x-2}+6\\\\Draw:\ y=\dfrac{3}{x}\\\\shift\ 2\ units\ right\ and\ 6\ units\ up.$

$y=\sqrt{x-2}+8\\\\Draw:\ y=\sqrt{x}\\\\shift\ 2\ units\ right\ and\ 8\ units\ up.$
The answer is the first coordinate of the intersection point of the graphs:
x = 3

3 0

3 years ago

Read 2 more answers

Angle XYZ = 2X° and angle PQR = (8X -20)°. If angle XYZ and angle PQR are supplementary, find the measure of each angle. Angle P

Alchen [17]

Answer:

$PQR = 140$

Step-by-step explanation:

Given

$XYZ = 2X$

$PQR = 8X - 20$

Required

Find PQR

Since both angles are supplementary, we have:

$XYZ + PQR = 180$

This gives:

$2X + 8X - 20 = 180$

$10X - 20 = 180$

Collect Like Terms

$10X = 20 + 180$

$10X = 200$

Divide through by 10

$X = 20$

Substitute 20 for X in $PQR = 8X - 20$

$PQR = 8 * 20 -20$

$PQR = 140$

7 0

3 years ago

Can someone help me Please

alisha [4.7K]

Jane: Think: the hypotenuse of her ramp is 14 inches and the angle opposite the rise is 30 degrees. Thus, cos 30 deg = (adj side) / (hyp) = (adj side) / (14 in).

Solving for (adj side), we get (adj side) = (14 in)(sqrt(3)/2) = 7 sqrt(3) inches.

3 0

3 years ago

Which is a true statement about 7 and 14?

Ksju [112]

7 and 14 can be divided in to two

7 0

3 years ago

-0.4a + 3 = 7 a = plz help

Papessa [141]

Answer:

a = -10

Step-by-step explanation:

-0.4a + 3 = 7

subtract 3 from each side

-0.4a + 3-3 = 7-3

-.4a = 4

Divide each side by -.4

-.4a/ -.4 = 4/-.4

a = - 10

4 0

3 years ago