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Lubov Fominskaja [6]
3 years ago
6

A disk of radius 25.0cm turns about an axis through the center. The pull on the string produces a linear acceleration a(t)=At on

the ball The disk starts from rest and after 3 seconds, linear a(3)=1.80m/s2. Find A and then write an expression for the angular acceleration α(t).
Physics
1 answer:
Svetlanka [38]3 years ago
3 0

Answer:

The value for  A  is A= 0.6

The angular acceleration is  \alpha (t) =  2.4 \ t \ m/s^2

Explanation:

From the question we are told that  

    The radius of the disk is  r =  25.0 \ cm  =  0.25 \ m

     The linear acceleration is  a(t) = At

     At time   t =  3 \ s

     a(3) =  1.80 \ m/s^2

Generally angular acceleration is  mathematically represented as  

         \alpha(t)  =  \frac{a(t)}{r}

Now  at t = 3 seconds  

         a(3) =  A *  3

=>      1.80 =  A  *  3  

=.>       A =  0.6

So  therefore

             a(t) =  0.6 t  

Now  substituting this into formula for angular acceleration

        \alpha (t) =  \frac{0.6 t }{R}

substituting for  r  

         \alpha (t) =  \frac{0.6 t }{0.25}

         \alpha (t) =  2.4 \ t \ m/s^2

 

     

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Explanation:

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A 200-Ω resistor is connected in series with a 10-µF capacitor and a 60-Hz, 120-V (rms) line voltage. If electrical energy costs
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Answer:

Cost to leave this circuit connected for 24 hours is $ 3.12.

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Substitute the given values

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