During low-intensity activity, your body obtains most of its energy from

Please help me.

navik [9.2K]

Vf=(35.0)+(-9.8)(2)
the answer would be 15.4 m/s

4 0

4 years ago

Which statements best describe the atoms of the gas neon? Check all that apply.

Anni [7]

What are the statements?

5 0

3 years ago

Read 2 more answers

A capacitor is constructed of two large, identical, parallel metal plates separated by a small distance d. A battery fully charg

Alja [10]

The capacitance of a capacitor of a parallel plate is given by:

$C=\frac{kA\cdot\epsilon_o}{d}$

Where:

$\begin{gathered} \epsilon_o=_{\text{ }}Vacuum_{\text{ }}permittivity \\ k=_{\text{ }}Dielectric_{\text{ }}constant=2 \\ A=_{\text{ }}Area_{\text{ }}of_{\text{ }}the_{\text{ }}plates \\ d=_{\text{ }}distance_{\text{ }}betwen_{\text{ }}the_{\text{ }}plates \end{gathered}$

We also know:

$\begin{gathered} Q=\frac{q}{V} \\ so\colon \\ \frac{q}{V}=\frac{kA\cdot\epsilon_o}{d} \\ V=\frac{qd}{kA\cdot\epsilon_o} \\ if \\ k=2 \\ V=\frac{1}{2}(\frac{qd}{kA\cdot\epsilon_o}) \end{gathered}$

As we can see the voltage halves

And since:

$\begin{gathered} E=\frac{V}{d} \\ W=qV \end{gathered}$

We can conclude that electric field and also the energy halve

5 0

1 year ago

How long does it take neptune to rotate on its axis

Phoenix [80]

Roughly about seven hundred days

6 0

3 years ago

Two moles of neon gas at 25oC and 2.0 atm is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. F

bazaltina [42]

Answer:

The end temperature is 174 °C

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

So, being:

P= 2 atm
V=?
n= 2 moles
R= 0.082 $\frac{atm*L}{mol*K}$
T= 25 °C= 298 °K

and replacing:

2 atm*V= 2 moles* 0.082 $\frac{atm*L}{mol*K}$ *298 K

you get:

$V=\frac{2 moles* 0.082\frac{atm*L}{mol*K} *298 K}{2 atm}$

V= 24.436 L

Now, two moles of neon gas is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. Then you know:

P= 1 atm
V= 3*24.436 L=73.308 L

n= 2 moles
R= 0.082 $\frac{atm*L}{mol*K}$
T= ?

Replacing:

1 atm*73.308 L= 2 moles* 0.082 $\frac{atm*L}{mol*K}$ *T

Solving:

$T=\frac{1 atm*73.308 L}{2 moles* 0.082\frac{atm*L}{mol*K}}$

T= 447 °K= 174 °C (being 0°C=273 °K)

<u><em>The end temperature is 174 °C</em></u>

5 0

3 years ago