This question is incomplete. The attached image was obtained online
Answer:
41 square units
Step-by-step explanation:
Looking at diagram that was attached, we can see that the Polygon s the combination of a square and a triangle.
In square CDEF we have:
The lengths of the side of the square= 4 units
Hence, the area of square is: length ²
Area of square= 4²
=16 square units
Also, in ΔBFA we have:
The base of the triangle is calculated as
=6 + 4= 10 units
height of the triangle is: FA= 5 units
The formula for Area of a triangle = 1/2 × Base × Height
Hence, we have area of ΔBFA as:
= 1/2 × 10 × 5
Area= 25 square units
The Area of the Polygon = Area of the square + Area of the triangle
16 square units + 25 square units
= 41 square units
Answer:
feet
Step-by-step explanation:
Answer:
x=12
Step-by-step explanation:
16x - (8x + 6) =90
The first step is to distribute the - sign
16x -8x -6 =90
Now we combine the like terms
8x-6 = 90
Add 6 to each side
8x-6+6 = 90+6
8x = 96
Divide each side by 8
8x/8 = 96/8
x =12
Answer:
Length = 18.099 ft
Width = 11.049 ft
Step-by-step explanation:
let the length of the field be x ft
and the width be y ft
as per the condition given in problem
x=2y-4 -----------(A)
Also the area is given as 200 sqft
Hence
xy=200
Hence from A we get
y(2y-4)=200
taking 2 as GCF out
2y(y-2)=200
Dividing both sides by 2 we get
subtracting 100 from both sides
Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form
Here in our case
a=1
b=-1
c=-100
Putting those values in the formula and solving them for y
Solving first
Solving second one
Which is wrong as the width can not be in negative
Our width of the field is
y=11.099
Hence the length will be
x=2y-4
x=2(11.049)-4
x=22.099-4
x=18.099
Hence our length x and width y :
Length = 18.099 ft
Width = 11.049 ft