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GuDViN [60]
2 years ago
8

Solve each of the following equations 1)x+8-15

Mathematics
1 answer:
FromTheMoon [43]2 years ago
7 0

Answer:

x - 7

Step-by-step explanation:

x + 8 - 15

Subtract 15 - 8 = 7

x  - 7

<u><em>~Lenvy~</em></u>

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Priya was busy studying this week and ran 7 fewer miles than last week. She ran 9 times as far as Elena ran this week. Elena onl
m_a_m_a [10]

Answer:

1) The number of miles Priya ran last week was 43 miles

2) The way Elena found Priya's miles is faster compared to the way it was found here

Step-by-step explanation:

1) The number of miles Priya ran this week = The number of miles Priya ran last week - 7

The number of miles Priya ran this week = 9 × The number of miles Elena ran this week

The number of miles Elena ran this week = 4 miles

Therefore;

Let the number of miles Priya ran last week = x miles

The number of miles Priya ran this week = (x - 7) miles

Therefore, we have

(x - 7) = 9 × The number of miles Elena ran this week = 9 × 4 miles = 36 miles

x = (36 + 7) miles = 43 miles

The number of miles Priya ran last week = x miles = 43 miles

The number of miles Priya ran last week = 43 miles

2) From (x - 7) = 9 × The number of miles Elena ran this week = 9 × 4 miles = 36 miles, we have;

(x - 7) = 9 × 4

1/9(x - 7) = 4

Therefore, multiplying by 9, we have;

9 × 1/9(x - 7) = 9 × 4

(x - 7) = 9 × 4 = 36

x - 7 + 7 = 36 + 7

x = 43 miles

Therefore, the way Elena found Priya's miles is faster compared to the way it is found here

6 0
3 years ago
4=z/3<br>solve for z <br>z=8<br>z=12<br>z=2<br>z=7​
miv72 [106K]

Answer:

z=12

Step-by-step explanation:

eliminate fraction denominators

4=3

4=\frac{z}{3}4=3z

3⋅4=3⋅3

3 \cdot 4=3 \cdot \frac{z}{3}3⋅4=3⋅3z

2

Cancel multiplied terms that are in the denominator

3⋅4=3⋅3

3 \cdot 4=3 \cdot \frac{z}{3}3⋅4=3⋅3z

3⋅4=

3 \cdot 4=z3⋅4=z

3

Multiply the numbers

3⋅4=

12=

5 0
3 years ago
Write a number that has four digits with same number in all places, such as 4,444. circle the digit with the greatest value. und
siniylev [52]

Easy.

Your number would be 2,222 and you'd circle the first 2 (starting from the left) and underline the last 2(again, starting from the left).

The reason why you'd underline the last 2, is because the very last number would represent the ones place. The first 2 would be the thousands place. Meaning that 2,222 would translate to two-thousand two-hundred twenty-two.

4 0
3 years ago
In the right ΔABC, AN is the altitude to the hypotenuse. Find BN, AN, and AC, if AB=2√5 in and NC= 1 in.
kipiarov [429]

Answer:

BN=4\ \text{in}

AN=2\ \text{in}

AC=\sqrt{5}\ \text{in}

Step-by-step explanation:

Let BN=x

BC=c

NC=y=1\ \text{in}

AB=a=2\sqrt{5}\ \text{in}

AC=b

We have the relation

\dfrac{BC}{AB}=\dfrac{AB}{BN}\\\Rightarrow \dfrac{c}{a}=\dfrac{a}{x}\\\Rightarrow c=\dfrac{a^2}{x}\\\Rightarrow x+1=\dfrac{a^2}{x}\\\Rightarrow x^2+x=20\\\Rightarrow x^2+x-20=0\\\Rightarrow x=\frac{-1\pm \sqrt{1^2-4\times 1\times \left(-20\right)}}{2\times 1}\\\Rightarrow x=4,-5

\boldsymbol{BN=4\ \text{in}}

h=\sqrt{a^2-x^2}\\\Rightarrow h=\sqrt{(2\sqrt{5})^2-4^2}\\\Rightarrow h=2\ \text{in}

\boldsymbol{AN=2\ \text{in}}

b=\sqrt{h^2+y^2}\\\Rightarrow b=\sqrt{2^2+1^2}\\\Rightarrow b=\sqrt{5}\ \text{in}

\boldsymbol{AC=\sqrt{5}\ \text{in}}

8 0
3 years ago
The gravitational force produced between any two objects kept 2.5×10^4 km apart is 580 N . At what distance should they be kept
DochEvi [55]

Answer:

Formula for gravitational force    F = G M1 * M2 / R^2  where G is the gravitational constant

F2 / F1 = (R1 / R2)^2 = 1/2         where F2 is the required force

R2 = (2)^1/2  R1     distance for R2 to be 1/2 force at R1

Since force is proportional to the square of the distance of separation, increasing the distance of separation by 2^2 will halve the force

7 0
3 years ago
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