3 years ago

(28 and 29) I really need help

Mathematics

1 answer:

scoundrel [369]3 years ago

5 0

Answer:

28 is 11/60

29 is 7/30

Step-by-step explanation:

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Two vertical poles of length 10 and 12 feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the

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Answer:

$L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft$

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

$x^{2} +10^{2}=L_{1} ^{2} \\x^{2} + 100 = L_{1} ^{2}$

Take the square root of both sides

$\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\ \sqrt{x^{2}+100}= L_{1}$

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

$(17-x)^{2}+12^{2}=L_{2} ^{2} \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}$

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Amount of cable used, L = L1 + L2

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3 years ago

What is this this sos 3x-y=3? (x,y)=?

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Rewrite the equation;

3x-y=3
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Linear equation.

I'm unsure of what the second part asks. Can you rewrite the given question?

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Hope it helps..

Have a great day!!

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awww omg that made my night thank u !

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