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lidiya [134]
2 years ago
12

Bryan lives 4/5 mi from the library. Jayden lives 0.72 mi from the library. Who lives farther from the library? How much

Mathematics
2 answers:
loris [4]2 years ago
8 0

Answer:Bryan lives farther from the library, 4/5 mi =0.80 mi, and 0.80 is more than 0.72, so Bryan lives farther

Step-by-step explanation:

Murrr4er [49]2 years ago
6 0

Answer:

Bryan Lively Professional Records Browse Bryan's professional profiles below to see current job title, work email address, place of employment and phone number. Showing 11 of 11 Results i think

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The average weight of a medium size egg is found to be 3.2 oz, with a standard deviation of 0.13 oz. What is the heaviest egg (t
Over [174]

Answer:

We are 95% confident that the average weight of the heaviest egg that is still medium size is 3.52 oz

Step-by-step explanation:

Mean = 3.2 oz, sd = 0.13 oz

Assuming there are 3 heavy eggs, n= 3, degree of freedom = n-1 = 3-1 = 2, t-value corresponding to 2 degrees of freedom and 95% confidence level is 4.303

Error margin = t×sd/√n = 4.303×0.13/√3 = 0.32 oz

Upper limit (heaviest egg that is still medium size) = mean + error margin = 3.2 + 0.32 = 3.52 oz

3 0
3 years ago
PLSS HELPP I'm Desperate
andrey2020 [161]

Answer:

20      2 x 20 =40 per min  

Step-by-step explanation:

we know u desperate hehe  lol

but

5 0
2 years ago
A rectangular prism has a volume of 100 cubic meters. One of the dimensions is 5 meters. Which pair of measurements could be the
natali 33 [55]

Answer:

1, 4, and 5

Step-by-step explanation:

1 is correct because 5*5=25*4=100

2 is incorrect because 5*5=25*5=125

3 is incorrect because 5*4=20*4=80

4 is correct because 5*20=100*1=100

5 is correct because 5*2=10*10=100

6 is incorrect because 5*10=50*10=500

4 0
3 years ago
Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show
Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is P(x \ge 60)=0.0901

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

        in every 1000 children a particular genetic defect occurs to 1

        The number of sample selected is n= 50,000

The probability of observing the defect is mathematically evaluated as

              p = \frac{1}{1000}

                 = 0.001

The probability of not observing the defect is mathematically evaluated as

            q = 1-p

               = 1-0.001

               = 0.999

The mean of this probability is mathematically represented as

                 \mu = np

Substituting values

                \mu = 50000*0.001

                    = 50

The standard deviation of this probability is mathematically represented as

   \sigma = \sqrt{npq}

Substituting values

      = \sqrt{50000 * 0.001 * 0.999}

     = \sqrt{49.95}

     = 7.07

 the probability of detecting  x  \ge60 defects can be represented in as  normal distribution like

       P(x \ge 60)

in standardizing the normal distribution the normal area used to approximate P(x \ge 60) is the right of 59.5 instead of 60 because  x= 60 is part of the observation

The z -score is obtained mathematically as

                z = \frac{x-\mu }{\sigma }

                   = \frac{59.5 - 50 }{7.07}

                  =1.34

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

  The total area under the curve is 1

So

    P(x \ge 60) \approx P(z > 1.34)

                     = 1-P(z \le 1.34)

                    =1-0.9099

                  =0.0901

             

   

3 0
3 years ago
Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)
ElenaW [278]

\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

Then, we'll use the point-slope form to make the new equation, where m is the slope and (x_1,y_1) is a point on the line:

\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}

3 0
1 year ago
Read 2 more answers
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