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2 years ago

Bryan lives 4/5 mi from the library. Jayden lives 0.72 mi from the library. Who lives farther from the library? How much

Mathematics

2 answers:

loris [4]2 years ago

8 0

Answer:Bryan lives farther from the library, 4/5 mi =0.80 mi, and 0.80 is more than 0.72, so Bryan lives farther

Step-by-step explanation:

Murrr4er [49]2 years ago

6 0

Answer:

Bryan Lively Professional Records Browse Bryan's professional profiles below to see current job title, work email address, place of employment and phone number. Showing 11 of 11 Results i think

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What percent of 2000 is 160?<br> Show work

ArbitrLikvidat [17]

Hello from MrBillDoesMath!

Answer:

.08%

Discussion:

Let the percent be denoted "p". Then

2000 * p% = 160 => ( as p% = p/100)

2000* p/100 = 160 =>

20p = 160 =>

p = 8 or .08%

Regards,

MrB

5 0

2 years ago

Read 2 more answers

1 of 3

Nonamiya [84]

Answer:

y = -1/2x + 3.5

Step-by-step explanation:

The gradients of perpendicular lines multiply to make -1. The gradient of the line given is 2, so 2 multiplied by something gives us -1. 2 × -1/2 = -1. The gradient of the perpendicular line is -1/2

y = -1/2x + c

Now we can substitute x = 1 and y = 3 into the equation:

3 = -1/2(1) + c
3 = -1/2 + c
c = 3 + 1/2
c = 3 1/2 or 3.5 or 7/2

The equation of the line is y = -1/2x + 3.5

Hope this helps!

3 0

2 years ago

Tomas bought 80 tickets for rides at an amusement park. Each ride costs 5 tickets, and Tomas has been on x rides so far. Which e

Alex Ar [27]

Answer:

Option A, C and D are correct choices.

Step-by-step explanation:

Let x be the number of rides that Tomas has been on so far. Each ride costs 5 tickets. This means that cost of x rides will be 5x.

We are told that Tomas bought 80 tickets for rides at an amusement park.

To find the number of of tickets that Tomas has left we will subtract cost of x rides from total number of tickets that Thomas bought.

We can represent this information in an expression as: $80-5x$

Now let us see which of our given choices in equivalent to our expression.

A. $80-5x$

Upon looking at option A we can see that it is same as our expression, therefore, option A is the correct choice.

B. $80+5x$

We can see that in this expression cost of x rides in being added instead of subtraction, therefore, option B is not a correct choice.

C. $5(16-x)$

Upon distributing 5 we will get,

$80-5x$

Now this expression is same same as our expression, therefore, option C is the correct choice.

D. $-5x+80$

This expression is also same as our expression as we can rearrange the terms in this expression as: $80-5x$ , therefore, option D is a correct choice as well.

E. $5(16+x)$