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GrogVix [38]
3 years ago
11

Which word best describes a set of four or more different points that are all in the same plane

Mathematics
1 answer:
aleksandrvk [35]3 years ago
7 0

Answer:

Dimensional is your answer


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A random sample of the amounts for 22 purchases was taken. The mean was ​$42.97​, the standard deviation was ​$22.82​, and the m
Illusion [34]

Answer: a) 84 and b ) 2084

Step-by-step explanation:

Given : Sample standard deviation : s= $22.82

(Population standard deviation is unknown ) , so we use t-test.

Critical value or the​ 95% confidence intervals :t_{n-1}*=2.0

Formula to find the sample size :

n=(\dfrac{t^*\cdot s}{E})^2

a) E = 5

n=(\dfrac{(2)\cdot 22.82}{5})^2

n=(9.128)^2=83.320384\approx84

i.e. Required sample size : n= 84

b)  E = 1

n=(\dfrac{(2)\cdot 22.82}{1})^2

n=(45.64)^2=2083.0096\approx2084

i.e. Required sample size : n= 2084

8 0
3 years ago
Can someone help me out with this problem
Nostrana [21]
I need more information.
8 0
2 years ago
Help please! 10 points!
IgorC [24]

Answer:

21.6 or 22

Step-by-step explanation:

Triangles have same angles. This means that they are proportion.

50/27 = 40/x

when you cross multiply to solve x, 50x = 1080

so x = 21.6

If you have to nearest whole number, it will be 22

7 0
3 years ago
Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
3 years ago
What is the diameter of this circle?​
jeka57 [31]

Answer:

The diameter of the circle is 14cm

Step-by-step explanation:

3 0
2 years ago
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