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VLD [36.1K]
3 years ago
7

Solve each equation. Check your solution 2/5g=3/5

Mathematics
2 answers:
omeli [17]3 years ago
5 0
G= 3/2. 3/5 divided by 2/5 gives you g.
WITCHER [35]3 years ago
3 0

Answer:

g = 2/3 or  1 1/2  or 1.5

Step-by-step explanation:

I'm assuming you wanted to find g, so divide by 2/5 on each side.

that leaves g = 3/5 ÷ 2/5.

To divide fractions, cross multiply.

So  \frac{3}{5} *\frac{5}{2}.

This equals 15/10 or 3/2.

Therefore g = 3/2.

Check solution by multiplying 2/5 times 3/2.

2*3=6

5*2=10

6/10=3/5

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Second time posting this. Please help!! :)
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

\frac{480+24(x-40)}{x}

The numerator of the rational expression the money he earned for 'x' hours

The rate at which William is paid for each hour in excess of 40 hours 24.

x = 50 hours = (40 + 10 ) hours

The amount paid for excess 10 hours = 24 *10 = 240

Total amount earned for the week = 480 + 240 = 720

5 0
3 years ago
Um help! how do I do this?
valkas [14]
1/2 t-4(2+t)=20
1/2 t-8-4t=20
least common multiple=2
t-16-8t=40
-7t=40+16
-7t=56
t=56/-7=-8

Answer: t=-8

To check
-8/2 - 4(2-8)=-4-4(-6)=-4+24=20
5 0
3 years ago
Read 2 more answers
12. A flat, square roof needs a square patch in the corner to seal a leak. The side length of
NISA [10]

Answer:

Step-by-step explanation:

Area of the good part= area of whole roof - area of bad part

Since the roof is a square roof, the area will be calculated using the formulae for area of a square

Area of a square =length²

Area of good part =(x+12)²-x²

A= {(x+12)(x+12)} - x²

A = (x²+12x+12x+144) -x²

Open the bracket and rearrange the equation

A= x²-x²+24x+144

A=(24x+144) ft

5 0
3 years ago
Brad runs a lap every 5 minutes and Ty runs a lap every 4 minutes. If they started at the same time, when will they get to the b
olganol [36]
20 minutes. On brads 4th run and Ty’s 5th run they will be at the beginning at the same time.
5 0
3 years ago
The sum of two consecutive odd integers is 316. Find the two odd integers.
Tcecarenko [31]
1, 3, 5, 7, 9 ......
notice, there are consecutive odd integers, every other number
skip one, another, skip one, another and so on

so, from 1 to 3, is 1 + 2 =3
5 is 3 +2
7 is 5+2
and so on

let us pick an odd integer, hmmm say "a"
to find the next odd one, it'd be "a + 2" of course :)

we know their sum is 316
so \bf a+(a+2)=316\impliedby \textit{solve for "a"}

once you found "a", the next one is, well, "a + 2" :)
5 0
3 years ago
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