Answer:
Point of intersections are (0, -7) and (5, -2).
Step-by-step explanation:
From the graph attached,
A straight line is intersecting the circle at the two points (0, 7) and (5, -2).
Now solve algebraically,
Equation of the line → y = x - 7 -------(1)
Equation of the circle → (x - 5)² + (y + 7)² = 25 -------(2)
By substituting the value of y from equation (1) to equation (2)
(x - 5)² + (x - 7 + 7)² = 25
(x - 5)² + x² = 25
x² - 10x + 25 + x² = 25
2x² - 10x = 0
x² - 5x = 0
x(x - 5) = 0
x = 0, 5
From equation (1),
y = 0 - 7 = -7
y = 5 - 7 = -2
Therefore, point of intersections are (0, -7) and (5, -2).
Answer:
f^-1(x)=1/4x+2
Step-by-step explanation:
y=4x-8
change x and y
x=4y=8
switch sides
4y-8=x
add 8
4y=x+8
divide both sides by 4
y=1/4x+2
substitute f^-1(x) for y
f^-1(x)=1/4x+2
Its 11/12 , you need to divide the "wanted results" (every dog which is either black, with spots or both ) by every every possible result ( all dogs ). so 11/12=0.92
Answer:
this cannot be factored since nothing shares factorable groups/values
Step-by-step explanation:
hope this helps:)
