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pishuonlain [190]
3 years ago
5

I need answers for 1 and 2

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0

1. Slope 3/4, through (4,-1)

y = 3/4 x + b

-1 = 3/4(4) + b

-1 = 3 + b

-1 - 3 = b

-4 = b

y = 3/4 x - 4

2. Slope = - 1/2, through (3,0)

y = -1/2 x + b

0 = -1/2(3) + b

0 = -1.5 + b

0 + 1.5 = b

1.5 = b

y = -1/2 x + 1.5

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In the figure above, PQRS is a circle. If PQT and SRT<br>are straight lines, find the value of x.
Elena L [17]

Given:

PQRS is a circle, PQT and SRT  are straight lines.

To find:

The value of x.

Solution:

Since PQRS is a circle, PQT and SRT  are straight lines, therefore, PQRS isa cyclic quadrilateral.

We know that, sum of opposite angles of a cyclic quadrilateral is 180 degrees.

m\angle SPQ+m\angle QRS=180^\circ

81^\circ+m\angle QRS=180^\circ

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m\angle QRT+m\angle QRS=180^\circ             (Linear pair)

m\angle QRT+99^\circ=180^\circ

m\angle QRT=180^\circ-99^\circ

m\angle QRT=81^\circ               ...(i)

According to the Exterior angle theorem, in a triangle the measure of an exterior angle is equal the sum of the opposite interior angles.

Using exterior angle theorem in triangle QRT, we get

m\angle PQR=m\angle QRT+m\angle QTR

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