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erik [133]
2 years ago
9

Determine whether each relationship is a function

Mathematics
1 answer:
Mademuasel [1]2 years ago
8 0
It’s a function
hope you have a good day
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ANSWER CORRECT FOR BRAINLIEST
monitta

Answer:

3 2 /5 ×3

change 3 2 /5 into an improper fraction

then you will get 17 /5

after that you say 17/5 ×3/1

=(17×3)/ (5x1)

=51/5 (51÷5)

=10.2/ 10 1/5

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2 years ago
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3 years ago
Which quantity could go in the blank to make the equation true?
Leni [432]
You need to provide an equation for this to be solved
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2 years ago
Each month, Anna pays $630 in rent. How much rent does she pay over the course of 18 months?
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7 0
3 years ago
The volume V of a gas varies inversely as the pressure P and directly as the temperature A certain gas has a volume of 10 liters
Ad libitum [116K]

Answer:

Joint variation states that:

If z is directly proportional to x and inversely proportional to y,

i.e, z \propto x , z \propto \frac{1}{y}

then the equation is in the form: z = k\frac{x}{y} where k is the constant of variation.

From the given information: The volume V of a gas varies inversely as the pressure P and directly as the temperature

i.,e V \propto T , V \propto \frac{1}{P}

by definition of joint variation:

V = k\frac{T}{P}  .....[1] where k is the constant of variation.

It is also given that a certain gas has a volume of 10 liters(L) , a temperature of 300 kelvins(K), and a pressure of 1.5 atmosphere(atm).

Substitute these given values in [1] to solve for k;

10 = k\frac{300}{1.5}

Simplify:

10 = 200k

Divide by 200 both sides we have;

k = \frac{10}{200} =\frac{1}{20}

Now, if a gas has a temperature of 400 kelvins and a pressure of 5 atm.

To find the volume (V);

Now substitute the given data and value of k in [1] we have;

V = \frac{1}{20} \cdot \frac{400}{5} = \frac{20}{5} = 4

Therefore, the Volume of a gas is, 4 liters


5 0
3 years ago
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