Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
Answer:
3.6
Step-by-step explanation:
Answer:
Area of the rectangular park = 2/3 square mile
Let us assume the width of the rectangular park = x
Then
The length of the rectangular park = 2 2/3 * x mile
= 8x/3 mile
Then
Area of the rectangular park = Length * Width
2/3 = (8x/3) * x
2/3 = 8x^2/3
(2 * 3)/3 = 8x^2
2 = 8x^2
x^2 = 2/8
x^2 = 1/4
x^2 = (1/2)^2
x = 1/2
So the width of the park is 1/2 feet.
Step-by-step explanation:
Brainliest would be nice
