No solution of the system of equations y = -2x + 5 and -5y = 10x + 20 ⇒ 2nd answer
Step-by-step explanation:
Let us revise the types of solutions of a system of linear equations
- One solution
- No solution when the coefficients of x and y in the two equations are equal and the numerical terms are different
- Infinitely many solutions when the coefficients of x , y and the numerical terms are equal in the two equations
∵ y = -2x + 5
- Add 2x to both sides
∴ 2x + y = 5 ⇒ (1)
∵ -5y = 10x + 20
- Subtract 10x from both sides
∴ -10x - 5y = 20
- Divide both sides by -5
∴ 2x + y = -4 ⇒ (2)
∵ The coefficient of x in equation (1) is 2
∵ The coefficient of x in equation (2) is 2
∴ The coefficients of x in the two equations are equal
∵ The coefficient of y in equation (1) is 1
∵ The coefficient of y in equation (2) is 1
∴ The coefficients of y in the two equations are equal
∵ The numerical term in equation (1) is 5
∵ The numerical term in equation (2) is -4
∴ The numerical terms are different
From the 2nd rule above
∴ No solution of the system of equations
No solution of the system of equations y = -2x + 5 and -5y = 10x + 20
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86? I'm not sure, sorry.
I plugged in the x and y values of the point given
Answer:
25 hamburgers
88.50/3.50
Step-by-step explanation:
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The sums range from 2 to 12 of which 6 are even out of 11 possible sums.
There are 4 multiples of 3, two of which are odd.
So the number of even sums is 6 and there are 2 unique or odd multiples of 3.
So there are a total 6+2=8 outcomes we want out of 36 possible outcomes.
The probability is then 8/36 or 2/9
<h2>
Answer:</h2>
A. It is a many-to-one function.
<h2>
Step-by-step explanation:</h2>
Hello! It will be a pleasure to help to figure out what's the correct answer to this problem. First of all, we have the following function:
When plotting this function, we get the red graph of the function shown below. So let's solve this as follows:
<h3>A. It is a many-to-one function.</h3>
True
A function is said to be many-to-one there are values of the dependent variable (y-values) that corresponds to more than one value of the independent variable (x-values). To test this, we need to use the Horizontal Line Test. So let's take the horizontal line 
, and you can see from the first figure below that is mapped onto 
. so this is a many-to-one function.
<h3>B. It is a one-to-one function.</h3><h3>False</h3>
Since this is a many-to-one function, it can't be a one-to-one function.
<h3>C. It is not a function.</h3>
False
Indeed, this is a function
<h3>D. It fails the vertical line test.</h3>
False
It passes the vertical line test because any vertical line can intersect the graph of the function at most once. An example of this is shown in the second figure below.
