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soldi70 [24.7K]
3 years ago
15

Anyone mind helping me out?

Mathematics
1 answer:
Taya2010 [7]3 years ago
8 0

hey Friend here is your answer

angle VUX

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I have a number between 60 and 80. I have a remainder of 3 when divided by 4. I have a remainder of 1 when divided by 7. What nu
Murljashka [212]

Answer:

71

Step-by-step explanation:

Divide 71 by 7 and you get 10 and 1 leftover. Divide 71 by 4 and you get 17 with 3 leftover.

6 0
3 years ago
Help as soon as possible pleaseee
KiRa [710]

Answer:

(3x + 2)(x-4)

Step-by-step explanation:

3x² - 10x - 8 = 0

(splitting the middle term)

3x² -12x + 2x -8 = 0

3x(x-4) + 2(x-4) = 0

(3x + 2)(x-4) = 0

(3x + 2)(x-4) is the correct answer (option a)

3 0
3 years ago
Read 2 more answers
need helpA triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(
iogann1982 [59]

Answer:

2.5

Step-by-step explanation:

The dilation is 2.5. Using the point b(0,4) and B' (0,10), divide 10/4 you get 2.5.

7 0
3 years ago
A football quarterback enjoys practicing his long passes over 40 yards. He misses the first pass 40% of the time. When he misses
laila [671]

Answer:

Probability of missing two passes in a row is 0.08.

Step-by-step explanation:

Event E = A football player misses twice in a row.

P(E) = ?

Event X = Football player misses the first pass

P(X) = 0.4

Event Y = Football player misses just after he first miss

P(Y) = 0.2

Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:

P(E) = P(X).P(Y)

P(E) = 0.4*0.2

P(E) = 0.08

4 0
3 years ago
Michael jogs at 3 miles per hour and Jack runs at 4.5 miles per hour. If Michael starts at 2:00 pm and Jack starts on the same c
tresset_1 [31]

Answer:

It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.

Step-by-step explanation:

Micheal  runs 3 miles in one hour or 60 minutes.

In one minute he runs 3/60= 1/20  or 0.05miles.

Jack runs 4.5 miles in one hour or 60 minutes.

In one minute he runs 4.5/60= 45/600= 9/120= 3/40  or 0.075 miles.

So Jack is 0.075/0.05 = 1.5 times faster than Micheal.

or Micheal is 1.5 times slower than Jack.

Jack starts from 2:20 pm and at 3 pm he will run 0.075(40 minutes)= 3miles

Micheal start at 2:00 pm and at 3 pm he will run 0.05(60 minutes)= 3 miles

So at 3 pm both will have covered equal distance= 3miles.

It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.

3 0
3 years ago
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