Well let's see.
If the figure is split up into 10 pieces, then
each piece is 1/10 of the whole figure.
If 2 of the pieces are shaded, then
2/10 of the whole figure is shaded.
How many pieces are left ?
There were 10 pieces all together, and
2 of them are shaded. Hmmm. I think
there are probably (10 - 2) = 8 of them left
that are not shaded.
8 pieces makes 8/10 of the whole figure.
Answer: A. X= -5, Y= 3, Z= 4
Step-by-step explanation:
Answer:
4/675
Step-by-step explanation:
There can be 90 two-digit numbers ranging from 10 to 99. There will be
90 x 90= 8100 possibilities of randomly selecting and combining 2 entire two-digit numbers, if we find ax b to be distinct from bx a. When 10 is first chosen, there may be 9 two-digit numbers that could be combined within the required range for a product When 11 is chosen first, then the second two-digit number has 9 possibilities. 12 has seven options; 13 has six options; 14 has five options; 15 has four options; 16 has three options; 17 has two options; 18 has 2 options; and 19 has one option. It provides us 48 total choices so the likelihood that the combination of two randomly chosen two-digit whole numbers is one of theses these possibilities is thus 48/8100 = 4/675.
Answer:
A is true and B is false.
Step-by-step explanation:
x + 6.2 ≥ 10.9
Replace x for 4.7...
4.7 + 6.2 ≥ 10.9
10. ≥ 10.9 ( So this is true!)
x - 6.2 ≤ - 5
Replace x for 4.7...
4.7 - 6.2 ≤ -5
-1.2 is not ≤ -5 (So this is false!)
