Answer:
95% Confidence interval for y
= (-9.804, -5.979)
Lower limit = -9.804
Upper limit = -5.979
Step-by-step explanation:
^y= 2.097x - 0.552
x = -3.5
Standard error = 0.976
Mathematically,
Confidence Interval = (Mean) ± (Margin of error)
Mean = 2.097x - 0.552 = (2.097×-3.5) - 0.552 = - 7.8915
(note that x=-3.5)
Margin of Error is the width of the confidence interval about the mean.
It is given mathematically as,
Margin of Error = (Critical value) × (standard Error of the mean)
Critical value for 95% confidence interval = 1.960
Standard Error of the mean = 0.976
95% Confidence Interval = (Mean) ± [(Critical value) × (standard Error of the mean)]
CI = -7.8915 ± (1.960 × 0.976)
CI = -7.8915 ± 1.91296
95% CI = (-9.80446, -5.97854)
95% Confidence interval for y
= (-9.804, -5.979)
Hope this Helps!!!
Answer:
C. Angle Addition Postulate
Step-by-step explanation:
Answer: 500 calories
Set them as proportions
375/46=x/60
Multiply 60 to each side to eliminate fraction
Then you’ll get x=500
Answer:
Step-by-step explanation:
To find : Acceleration in first 15 min . Distance between two cities Average speed of journey
Solution:
Each horizontal block is 1/8 hr = 7.5 min
Each vertical block is 10 km/hr
Time Velocity km/hr
0 Min ( 0 hr) 0
15 Min (1/4 hr) 50
45 Min (3/4 hr) 50
60 MIn ( 1 hr) 100
90 Min ( 3/2 hr) 100
120 Min ( 2hr) 0
Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)
= 200 km/h²
Distance between two cities
= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)
= 25/4 + 25 + 75/4 + 50 + 25
= 125
Distance between two cities = 125 km
Average Speed of journey = 125/2 = 62.5 km/hr
Acceleration in first 15 min = 200 km/h²
Distance between two cities = 125 km
Average Speed of journey = 62.5 km/hr
Hope this helps..
