Okay, through simple division I'll give you the long side of the work. Known as Long Division: [This may turn out unaligned correctly, but hopefully it works.]
Question 1:
~~~ [][]816.82 ~ Answer. ~ Estimate to 816.8 or 817.
73 / 59628
~~~ 596
~~~ 584 ~ 73 goes into 596 8 times, giving us 584. Subtract and carry.
~~~~ 122
~~~~ []73 ~ 73 goes into 122 1 time, giving us 73. Subtract and carry.
~~~~~ 498
~~~~~ 438 ~ 73 goes into 498 6 times, giving us 438. Subtract and add a 0.
~~~~~~ 600
~~~~~~ 584 ~ 73 goes into 600 8 times, giving us 584. Subtract and add a 0.
~~~~~~~ 160
~~~~~~~ 146 ~ 73 goes into 160 2 times, giving us 146. Finalize the answer.
Question 2:
~~~ [][]6228.35 ~ Answer. Estimate to 6,228.4 or 6,228.
58 / 361245
~~~ 361
~~~ 348 ~ 58 goes into 361 6 times, giving us 348. Subtract and carry.
~~~~ 132
~~~~ 116 ~ 58 goes into 132 2 times, giving us 116. Subtract and carry.
~~~~~ 164
~~~~~ 116 ~ 58 goes into 164 2 times, giving us 116. Subtract and carry.
~~~~~~ 485
~~~~~~ 464 ~ 58 goes into 485 8 times, giving us 464. Subtract and add 0.
~~~~~~~ 210
~~~~~~~ 174 ~ 58 goes into 210 3 times, giving us 174. Subtract and add 0.
~~~~~~~~ 340
~~~~~~~~ 290 ~ 58 goes into 340 5 times, giving us 290. Finalize the answer.
Question 3:
~~~ [][]1631.12 ~ Answer. Estimate to 1,631.1 or 1,631.
64 / 104392
~~~ 104
~~~~ 64 ~ 64 goes into 104 1 time, giving us 64. Subtract and carry.
~~~~ 403
~~~~ 384 ~ 64 goes into 403 6 times, giving us 384. Subtract and carry.
~~~~~ 199
~~~~~ 192 ~ 64 goes into 199 3 times, giving us 192. Subtract and carry.
~~~~~~~ 72
~~~~~~~ 64 ~ 64 goes into 72 1 time, giving us 64. Subtract and add 0.
~~~~~~~~ 80
~~~~~~~~ 64 ~ 64 goes into 80 1 time, giving us 64. Subtract and add 0.
~~~~~~~~ 160
~~~~~~~~ 128 ~ 64 goes into 160 2 times, giving us 128. Finalize the answer.
I hope that helps, have a great rest of your day! ^ ^
{-Ghostgate-}
A) La distancia del Sol a Neptuno en notación científica es 45 x 10^8 km.
B) Júpiter se encuentra a 930.000.000 kilómetros del Sol.
C) La distancia del Sol a Neptuno es 30 veces mayor que la que hay a la Tierra.
Dado que la distancia entre la tierra y el sol es de 1,5 . 10˄8 km, la distancia entre la Tierra y Júpiter es de 9,3 . 10˄8 km y Neptuno está situado a 4.500.000.000 Km del Sol, para determinar:
A) Expresa en notación científica la distancia del sol a Neptuno
B) Calcula la distancia a la que está situado Júpiter respecto al Sol
C) Calcula cuantas veces es mayor la distancia del Sol a Neptuno que la que hay a la Tierra.
Deben realizarse los siguientes cálculos:
- A) 4.500.000.000 = 45 x 100.000.000
- 100.000.000 = 10^8
- 4.500.000 = 45 x 10^8
- B) 9.3 x 10^8 = X
- 100.000.000 = 10^8
- 9.3 x 100.000.000 = X
- 930.000.000 = X
-
C) Tierra = 150.000.000
- Neptuno = 4.500.000.000
- 150 = 1
- 4.500 = X
- 4500 / 150 = X
- 30 = X
Aprende más en brainly.com/question/1705769
Answer: D
Step-by-step explanation: Using pemdas parentheses is always first so the answer is D.
Answer:
You didn't tell me which one is the base or height
Step-by-step explanation:
Area of a triangle: 
1225*(1.578*10^-5)=1.933*10^-2
1.578*10^-5= 0.00001578
1225*0.00001578=0.0193305
0.0193305=1.933*10^-2