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g100num [7]
3 years ago
9

Construct a 95% prediction interval for y given x=-3.5, ^y= 2.097x - .552 and se= .976​

Mathematics
1 answer:
Rasek [7]3 years ago
3 0

Answer:

95% Confidence interval for y

= (-9.804, -5.979)

Lower limit = -9.804

Upper limit = -5.979

Step-by-step explanation:

^y= 2.097x - 0.552

x = -3.5

Standard error = 0.976

Mathematically,

Confidence Interval = (Mean) ± (Margin of error)

Mean = 2.097x - 0.552 = (2.097×-3.5) - 0.552 = - 7.8915

(note that x=-3.5)

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value for 95% confidence interval = 1.960

Standard Error of the mean = 0.976

95% Confidence Interval = (Mean) ± [(Critical value) × (standard Error of the mean)]

CI = -7.8915 ± (1.960 × 0.976)

CI = -7.8915 ± 1.91296

95% CI = (-9.80446, -5.97854)

95% Confidence interval for y

= (-9.804, -5.979)

Hope this Helps!!!

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Answer:

I believe the answer would be 186

Step-by-step explanation:

241-55=186

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You draw a marble from a bag that has 3 red, 4 blue, and 5 green, you also flip a fair coin. What is the probability you will dr
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3 years ago
What is the solution of log4(2x-6)=2
Flauer [41]

Answer: x=11

Step-by-step explanation:

Remembert that, by definition:

log_b(x)=y → b^y=x

Then, you can rewrite log_4(2x-6)=2 in exponential form:

4^2=2x-6

Now you can solve for the variable "x":

Add 6 to both sides of the equation:

4^2+6=2x-6+6

22=2x

And finally you must divide both sides of the equation by 2, then:

\frac{22}{2}=\frac{2x}{2}\\\\x=11

3 0
3 years ago
A salesperson is paid a flat rate plus a fixed percentage of her sales. Last month, she sold $16,000 worth of goods and was paid
MA_775_DIABLO [31]

Answer:

She will be paid $1,350

Step-by-step explanation:

Let the flat rate be $x and the fixed percentage be y% = y/100

Thus, her payment per month will be

x + (y% of monthly amount) = Payment

For the 1st month, her pay calculations will look like this;

x + y/100 *(16,000) = 1,600

x + 160y = 1600 •••••••••(i)

For the month before the last, her calculations would be;

x + y/100(12,000) = 1,400

x + 120y = 1,400 ••••••••(ii)

It is these two equations that we now solve simultaneously.

We can directly get this by subtracting equation ii from i

That would be;

(x-x) + (160y-120y) = (1600-1400)

40y = 200

y = 200/40

y = 5%

To get x, we can substitute in any of the equations

Let us use equation ii

x + 120(5) = 1,400

x + 600 = 1,400

x = 1,400-600

x = $800

Thus, for $11,000 , the equation will be as follows;

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4 0
3 years ago
Read 2 more answers
If x and y are both negative when is x-y positive
jarptica [38.1K]
Hmm

let's try some numbers

we have 3 scenarios
x>y
x=y
x<y

x>y
x=-1 and y=-2
x-y=-1-(-2)=-1+2=1
it's positive when x>y

x=y
x=-1, y=-1
-1-(-1)=-1+1=0
nope

x<y
x=-2 and y=-1
-2-(-1)=-2+1=-1
nope


x-y is positive when 0>x>y
4 0
3 years ago
Read 2 more answers
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