Question

Analyze and solve this partially completed galvanic cell puzzle. There are 4 electrodes each identified by a letter of the alphabet, A through D. The values in the partially completed grid are measured cell potentials for a cell consisting of electrode #1 and electrode #2. You may assume that each galvanic cell was properly constructed with the appropriate metals and solutions and that all the measured values in the grid are accurate.
electrode #1 ?

C

B

D

A

electrode #2?

Ecell(volts)

Ecell(volts)

Ecell(volts)

Ecell(volts)

C

0

0.91

0.62

0.26

B

0.91

0

1.53

D

0.62

1.53

0

0.36

0 volts

0.10 volts

0.26 volts

0.36 volts

0.55 volts

0.62 volts

0.65 volts

0.88 volts

0.98 volts

1.17 volts

1.27 volts

1.79 volts

1.89 volts

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is  $E_{cell}__{AC}} = 0.94$

Explanation:

  From the question we are told that

          the cell voltage for AD is  $E_{cell}__{AD}} = 1.56V$

From the data give we can see that

               $E_{cell}__{AD}} - E_{cell}__{BD}} = E_{cell}__{AB}}$

i.e           $1.56 - 1.53 = 0.03$

   In the same way we can say that

              $E_{cell}__{AD}}-E_{cell}__{CD}} = E_{cell}__{AC}}$

=>        $E_{cell}__{AC}}=1.56- 0.62$

                       $E_{cell}__{AC}} = 0.94$