1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
drek231 [11]
2 years ago
5

Realiza los cálculos para determinar la cantidad de KOH 90%, que se necesita para preparar 100 ml de solución 1N.

Chemistry
1 answer:
attashe74 [19]2 years ago
8 0

Answer:

6.23 KOH 90% son necesarios

Explanation:

Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.

Para responder esta pregunta se requiere hallar los equivalentes = Moles de KOH para preparar 100mL = 0.100L de una solución 1N. Haciendo uso de la masa molar de KOH y del porcentaje de pureza del KOH se pueden calcular los gramos requeridos para preparar la solución así:

<em>Equivalentes KOH:</em>

0.100L * (1eq / L) = 0.100eq = 0.100moles

<em>Gramos KOH -Masa molar: 56.1056g/mol-:</em>

0.100moles * (56.1056g/mol) = 5.61 KOH se requieren

<em>KOH 90%:</em>

5.61g KOH * (100g KOH 90% / 90g KOH) =

<h3>6.23 KOH 90% son necesarios</h3>
You might be interested in
The reaction 3NO ---&gt; N2O + NO2 is found to obey the rate law Rate = k[NO]^2^. If the first half-life of the reaction is foun
agasfer [191]

Answer:

8.0 s.

Explanation:

Hello,

In this, case, by knowing that the half-life time allows as to compute the rate constant in terms of the initial concentration as shown below:

k=\frac{1}{[NO]_0*t_{/2}} = \frac{1}{[NO]_0*2.0}=\frac{1}{2[NO]_0}

Therefore, the fourth half-life time implies that the concentration is 1/16 the initial one, therefore:

t_{1/2}^{4th}=\frac{1}{k/16}= 8.0s

That is analyzed considering that if the initial concentration is 1M the first half-time is at 0.5M, the second at 0.25M, the third at 0.125M and the fourth at 0.0625M which is 16 times smaller than 1M.

Best regards.

6 0
2 years ago
HELP ASAP PLEASE!!!
Mashcka [7]
I believe it’s false
3 0
3 years ago
Which methods would be suitable for determining the concentration of an aqueous solution of KMnO4? I. Visible spectrophotometry
Elodia [21]

Answer:

C

Explanation:

Since the solution have an observable color, that means that it absorbs light in the visible region hence it can be determined by colorimetry. Secondly, KMnO4 is a reducing agent which can be titrated against an oxidizing agent and it's concentration accurately determined.

3 0
3 years ago
When heat is added to the substances, the atoms being to?
uranmaximum [27]

Answer:

atoms move faster

Explanation:

Space is produced when substances are heated. The atoms became extremely energetic and began to move much quicker than usual. When this happens, energy is released in the form of heat, light, and so on. As a result, kinetic energy rises and atoms collide more frequently.

3 0
1 year ago
Explain why some atoms gain or lose electrons to form ions.
anygoal [31]
Because some atoms<span> are more stable when they </span>gain or lose<span> an </span>electron<span> and </span>form ions<span>.</span>
7 0
3 years ago
Read 2 more answers
Other questions:
  • Liver cells require a great deal of energy which cell organelles would you except to appear in large number as a result
    14·1 answer
  • Surface currents are caused by ______ .
    8·2 answers
  • Can somebody help pls??????????
    10·2 answers
  • 6 questions for 100 points
    5·2 answers
  • The molar masses of three gases, A, B, and C, are 4 grams, 16 grams, and 32 grams respectively. Which sentence represents the ef
    9·2 answers
  • What is the volume of the water in graduated cylinder B?*
    6·1 answer
  • What's the Lewis dots for CCl4
    12·1 answer
  • Which of the following describes the greenhouse effect
    12·2 answers
  • Explain chromatography​
    15·1 answer
  • Doraemon part of the water cycle heat from the Sun causes liquid to change into water vapor Which Resident to the atmosphere whi
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!