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3 years ago

(secA+cosA)(secA-cosA)=tan^2A+sin^2A

Mathematics

1 answer:

vlabodo [156]3 years ago

8 0

$(\sec A+\cos A)(\sec A-\cos A)=\sec^2A-\cos^2A$

$\sec^2A-\cos^2A=(1+\tan^2A)-(1-\sin^2A)$

$(1+\tan^2A)-(1-\sin^2A)=\tan^2A+\sin^2A$

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3 years ago

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Gennadij [26K]

Answer:

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Step-by-step explanation:

Given

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