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kupik [55]
4 years ago
9

What is the value of x

Mathematics
1 answer:
Anit [1.1K]4 years ago
8 0
The answer maybe 1/2
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Roman55 [17]

Answer:

pizza hut

Step-by-step explanation:

top 10 pizza places true or false

3 0
3 years ago
Aflati triunghiul dreptunghic ABC daca a) a=17 si b=8<br> b) c=6<br> C=42 grade
Ierofanga [76]
Answer is c c=42 grade
7 0
4 years ago
Pls help<br> Will mark brainliest
Romashka [77]

Answer:

\large \boxed{ \boxed{ \tt{g(4) =  -  \frac{16}{3}  \longrightarrow \:  \: Improper \:  \:  Fraction \:  \:  }}} \\  \large \boxed{ \boxed{ \tt{g(4) =  - 5 \frac{1}{3}  \longrightarrow \:  \: Mixed \:  \:  Fraction \:  \:  }}}

Step-by-step explanation:

We are given the function below:

\large{g(x) =  \frac{4x}{3x - 15} }

To find g(4), we simply substitute x = 4 in the equation.

\large{g(4) =  \frac{4(4)}{3(4) - 15} }

Then evaluate the value and simplify in the simplest form.

\large{g(4) =  \frac{16}{12 - 15} } \\  \large{g(4) =  \frac{16}{ - 3} } \\  \large{g(4) =  -  \frac{16}{3} }

Therefore, the value of g(4) is - 16/3

<u>Mixed</u><u> </u><u>Fraction</u><u> </u><u>Form</u>

<u>\large{g(4) =  - 5 \frac{1}{3} }</u>

5 0
3 years ago
The figure the Floor Plan of a balcony ,it consists of △ABC and semi-circle ,
ivanzaharov [21]

Step-by-step explanation:

(a) In right triangle ABC,

AC^2 =AB^2 +BC^2  \\  =  {12}^{2} +  {5}^{2}   \\  = 144 + 25 \\  = 169 \\  AC =  \sqrt{169}  \\  \therefore \: AC =  13\: m \\  \\ AC \: is \: the \: diameter \: of \: semicircle \\  \therefore \: r =  \frac{1}{2} \times  AC = \frac{1}{2} \times 13 = 6.5 \: m \\  Circumference \:of \:semi-circle \\ C = \pi \: r = 3.14 \times 6.5 = 20.41 \:m\:

Perimeter of Balcony = 12 + 5 + 20.41 = 37.41 m

(b) Area of balcony

=\frac{1}{2}\times 12\times 5+\frac{1}{2} \pi r^2 \\\\=\times 6\times 5+\frac{1}{2} \times 3.14\times (6.5)^2 \\\\=30+\frac{1}{2} \times 3.14\times42.25\\\\= 30+\frac{1}{2} \times 132.665\\\\= 30 + 66.3325\\\\= 96.3325 \:m^2 \\\\\approx 96. 33\:m^2

8 0
4 years ago
HELP TIMER Write the equation of a hyperbola centered at the origin with x-intercept +/- 4 and foci of +/-2(squareroot 5)
meriva

Given:

x-intercepts of the hyperbola are ±4.

The foci of hyperbola are \pm 2\sqrt{5}.

Center of the hyperbola is at origin.

To find:

The equation of the hyperbola.

Solution:

The general equation of a hyperbola:

\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1            ...(i)

Where, (h,k) is the center of the hyperbola, ±a are x-intercepts, (\pm c,0) are foci.

Center of the hyperbola is at origin. So, h=0 and k=0.

x-intercepts of the hyperbola are ±4. So,

\pm a=\pm 4

a=4

The foci of hyperbola are \pm 2\sqrt{5}.

\pm c=\pm 2\sqrt{5}

c=2\sqrt{5}

We know that,

a^2+b^2=c^2

(4)^2+b^2=(2\sqrt{5})^2

16+b^2=20

b^2=20-16

b^2=4

Taking square root on both sides, we get

b=\sqrt{4}                    [b>0]

b=2

Substituting h=0,k=0,a=4,b=2 in (i), we get

\dfrac{(x-0)^2}{4^2}-\dfrac{(y-0)^2}{2^2}=1

\dfrac{x^2}{4^2}-\dfrac{y^2}{2^2}=1

Therefore, the correct option is (d).

4 0
3 years ago
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