Answer:
Put a picture of the whole thing
Step-by-step explanation:
Well V= 5•7•5
Therefore V= 175
Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
1. D. 4 x 4 x 4 x 4 x 4
2. B. 6³ (6 x 6 x 6 = 216)
3. D. (8², 100^1, 11², 5³)
4. D. Sum (There's No addition anywhere in that equation)
5. C. h (Because there's no number before the h²)
6. C. 24
7. C. Raise 9 to the 2nd power (Follow PEMDAS, after doing the parentheses, you need to do the exponents, and C. you need to the exponents)
8. A. 4xy
9. C. 18 (I followed PEMDAS, and received the answer 18)
10. B. 49
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<em>I hope this helps, and Happy Holidays! :)</em>
Answer: B
Negative a squared b and 5 a squared b
Step-by-step explanation:
Given that:
Negative a squared b + 6 a b minus 8 + 5 a squared b minus 6 a minus b. That is,
- a^2b + 6ab - 8 + 5a^b - 6a - b
Collecting the like term by rearranging the expression
5a^2b - a^2b + 6ab - 6a - b
The like terms in the expression above are
5a^2b - a^2b.
The correct option is B:
Negative a squared b and 5 a squared b or (-a^2b and 5a^b)
