All categories

3 years ago

Please I'm stuck and only you guys can help me I need to find y. I already find x

Mathematics

1 answer:

Vinvika [58]3 years ago

5 0

Answer:

what is the problem??like y=x+????

you didn't post the equation

You might be interested in

Help me pleas i dont get it

Tasya [4]

I got you!!!!!!!!!!!!!!!

8 0

4 years ago

Read 2 more answers

Number 12 please help! Thanks!

almond37 [142]

#1. 712.5
#2. 1185
#3 .517.5

7 0

3 years ago

Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x

Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

$y=a(x-h)^2+k$

(where (h, k) is the vertex)

Given:

vertex = (1, -108)

$\implies y=a(x-1)^2-108$

Given:

y-intercept = (0, -105)

$\implies a(0-1)^2-108=-105$

$\implies a(-1)^2=-105+108$

$\implies a=3$

Therefore:

$\implies y=3(x-1)^2-108$

The x-intercepts are when y = 0

$\implies 3(x-1)^2-108=0$

$\implies 3(x-1)^2=108$

$\implies (x-1)^2=36$

$\implies x-1=\pm \sqrt{36}$

$\implies x=1\pm 6$

$\implies x=7, x=-5$

Therefore, the x-intercepts are (7, 0) and (-5, 0)

7 0

2 years ago

What is the equation of a line in point slope form that passes through (-2, -6)

shepuryov [24]

I hope this helps you

6 0

3 years ago

What is the area of this figure?

ludmilkaskok [199]

Answer:

$\large\boxed{\large\boxed{42 unit^2}}$

Explanation:

The figure is not a regular hexagon. It is an irregular hexagon.

Please, find attached the picture with the original question and the figure.

You can split the figure into two triangles and one rectangle.

The rectangle has dimensions: 7units × 4units, thus its area is 28 units².

Both the upper triangle and lower triangle have base 7 units and height 2 units.

Hence the area of each triangle is:

$area=(1/2)base\times height$

$area=(1/2)7units\times 2units = 7units^2$

Hence, the area of the hexagon is:

$28units^2+7units^2+7units^2=42units^2$

3 0

4 years ago