X^6-36= (x^3+6)(x^3-6)
the answer to the question
Answer:
The mean.
Step-by-step explanation:
I would use the mean as the measure of central tendency.
It is the best representation of the data as the variability isn't high; I'd only use the median if outliers are present because outliers don't affect it.
Because there are no outliers here, the mean is better.
Hopefully I helped :)
Ok
we see the leading coefient is positive, and the degre is 3 so it goes from bottom left to top right
if we factor to find x intercepts or zeros we get f(x)=(x)(x-9)(x-1)
so it crosses at x=0,1,9
that would be the 4th graph (the one that goes down to y=-90)
2.75! Good luck hope you do good