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Artist 52 [7]
2 years ago
13

Students in a high school mathematics class decided that their term project would be a study of

Mathematics
1 answer:
weeeeeb [17]2 years ago
8 0

The parameter of interest in this scenario is the proportion of all 1,000 students within the school who have "strict" parents or guardians.

<h3>How to calculate a test statistic?</h3>

In Mathematics, the test statistics of a given sample is calculated by using this formula:

Z=\frac{x\;-\;u}{\frac{\sigma}{\sqrt{n} } }

<u>Where:</u>

  • x is the sample mean.
  • u is the mean.
  • is the standard deviation.
  • n is the sample size.

In conclusion, a possible test statistic which can be used to estimate this parameter is the proportion of all students who have "strict" parents or guardians, based on the collected sample.

Read more on test statistic here: brainly.com/question/4621112

#SPJ1

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A line segment has endpoint j(2,4) and l(6,8).the point k is the midpoint of jl.what is an equation of a line perpendicular to j
GenaCL600 [577]
The equation of the line is:
 y-yo = m (x-xo)
 Where,
 m = (y2-y1) / (x2-x1)
 Substituting values:
 m = (8-4) / (6-2)
 m = (4) / (4)
 m = 1
 Then, the equation is:
 y-4 = 1 * (x-2)
 Rewriting:
 y = x-2 + 4
 y = x + 2
 The midpoint is:
 k = ((x1 + x2) / 2, (y1 + y2) / 2)
 k = ((2 + 6) / 2, (4 + 8) / 2)
 k = ((8) / 2, (12) / 2)
 k = (4, 6)
 Then, the equation of the perpendicular line that passes through k is:
 y = -x + b
 Looking for b we have:
 6 = -4 + b
 b = 6 + 4
 b = 10
 Substituting:
 y = -x + 10
 Answer:
 An equation of a line perpendicular to jl and passing through k is:
 y = -x + 10
3 0
3 years ago
I need help i don’t understand
ch4aika [34]

9514 1404 393

Answer:

  A) J(-3, 1), ...

Step-by-step explanation:

All of the answer choices list point J' first, so it is convenient to use that as an example.

Point J on the given graph has coordinates (x, y) = (3, 2). The x-coordinate is 3 because the point is 3 units to the right of the y-axis.

The problem statement tells you to translate this point 6 units to the left. When you move it 6 units left, it will move left 3 units to the y-axis, then left 3 more units to have an x-coordinate of 3 -6 = -3. That is, each unit of movement to the left subtracts 1 from the x-coordinate. The x-coordinate of J is 3, so the final point J' will have an x-coordinate of 3 - 6 = -3.

At this point, you have enough information to make the correct answer selection. Only one answer choice has the x-coordinate of J' as -3.

__

The other coordinates are translated using similar logic. The y-coordinate of J is 2. Translating it down 1 unit subtracts 1 from the y-coordinate to make it be 2 -1 = 1. Then the coordinates of J' are (-3, 1).

We write the translation rule as ...

  (x, y) ⇒ (x -6, y -1)

This means the coordinates of each translated point have 6 subtracted from the original x-coordinate, and 1 subtracted from the original y-coordinate. The other coordinates of the figure are ...

  I(2, 4) ⇒ I'(2 -6, 4 -1) = I'(-4, 3)

  H(5, 5) ⇒ H'(5 -6, 5 -1) = H'(-1, 4)

  G(4, 1) ⇒ G'(4 -6, 1 -1) = G'(-2, 0)

3 0
3 years ago
Where is 2/4 on the number line with a number line of on 3 ticks?
KIM [24]
2 to the left is 3 your very welcome hope this helps
4 0
3 years ago
I need help!!!! Evaluate 4/7 + 8/3 in fraction form
Reptile [31]

Answer:

  • 3 5/21.
  • 68/21

Step-by-step explanation:

<u>Given equation:</u>

  • 4/7 + 8/3

<u>Solve:</u>

  • 4/7 + 8/3
  • = 12/21 + 56/21
  • = \frac{12 + 56}{21 + 0}
  • = 3 5/21.
  • = 68/21.
8 0
2 years ago
What can be used to determine the length of segment AB?
Vikki [24]

It depends on what you mean by "what can be used", you can use a protractor or ruler since it's a line segment. OR you can use the formula a^ + b^ = c^ to find out all the measurements.......

If you still can't find it, then, you can try to find the other measurements around that specific line segments. And it DEPENDS on what you choose to find the length of this segment.

( There's no picture on my screen, so I'm guessing that you didn't put any.. )

Well, I hope this can help you :3

STAY SAFE!! :)

6 0
3 years ago
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