Question

Quadrilateral EFGH has coordinates E(2a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of he

Answer 1

The formula of the midpoint of HE:
$\left(\dfrac{x_H+x_E}{2};\ \dfrac{y_H+y_E}{2}\right)$

We have H(0; 0) and E(2a; 2a). Substitute:
$\left(\dfrac{0+2a}{2};\ \dfrac{0+2a}{2}\right)=(a;\ a)$

Answer 2

Answer:

The answer is (a, a)