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kirill115 [55]
3 years ago
12

Quadrilateral EFGH has coordinates E(2a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of he

Mathematics
2 answers:
Gre4nikov [31]3 years ago
4 0
The formula of the midpoint of HE:
\left(\dfrac{x_H+x_E}{2};\ \dfrac{y_H+y_E}{2}\right)

We have H(0; 0) and E(2a; 2a). Substitute:
\left(\dfrac{0+2a}{2};\ \dfrac{0+2a}{2}\right)=(a;\ a)

gulaghasi [49]3 years ago
4 0

Answer:

The answer is (a, a)

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ANSWER:

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STEP-BY-STEP EXPLANATION:

We have that the equation in its slope-intercept form is the following:

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5 0
1 year ago
Find a5, when a1 =4, r=5
sasho [114]

Answer:

Answer: a5 = 2500

Step-by-step explanation:

For a geometric sequence:  

First term = a0  

Second term = a1 = a0*r  

Third term = a2 = a0*r^2  

Fourth term = a3 = a0*r^3  

....  

nth term = a(n-1) = a0*r^(n-1)  

Given: a1 = 4 = a0*r  

Also: r = 5  

So, a0*5 = 4 => a0 = (4/5)  

a5 = a(6-1) = Sixth term = a0*r^5 = (4/5)*5^5 = 2500  


Hope this helps

correct me if im wrong☺


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