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kirill115 [55]
3 years ago
12

Quadrilateral EFGH has coordinates E(2a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of he

Mathematics
2 answers:
Gre4nikov [31]3 years ago
4 0
The formula of the midpoint of HE:
\left(\dfrac{x_H+x_E}{2};\ \dfrac{y_H+y_E}{2}\right)

We have H(0; 0) and E(2a; 2a). Substitute:
\left(\dfrac{0+2a}{2};\ \dfrac{0+2a}{2}\right)=(a;\ a)

gulaghasi [49]3 years ago
4 0

Answer:

The answer is (a, a)

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