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3 years ago

Answer quickly, please. I need this. I will give brainliest to whoever answers first. You also get 25 points for this

Mathematics

1 answer:

sukhopar [10]3 years ago

3 0

** DISCLAMIER** am not completely sure. Please do not use my answer unless you are very desperate.

since O,R correspond with A,N I think you half F on each side and add it to 11.2 so
10 divided by 2 = 5
7 is already half.
5 + 7 is 12
12 + 11.2 = 23.2

IF THIS IS WRONG TRY 17
reason for 17:
10 + 7 = 17
If you look at both lines they look the same length as A, N.

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IrinaVladis [17]

Answer:

(3,6)

Step-by-step explanation:

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3 years ago

Verify that:

Lelu [443]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to verify that:

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$\displaystyle \left(\cos(x)\right)\left(\frac{\cos(x)}{\sin(x)}\right)=\csc(x)-\sin(x)$

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$\displaystyle \frac{\cos^2(x)}{\sin(x)}=\csc(x)-\sin(x)$

Recall that Pythagorean Identity: sin²(x) + cos²(x) = 1 or cos²(x) = 1 - sin²(x). Substitute:

$\displaystyle \frac{1-\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)$

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Simplify:

$\csc(x)-\sin(x)=\csc(x)-\sin(x)$

Problem 2)

We want to verify that:

$\displaystyle (\csc(x)-\cot(x))^2=\frac{1-\cos(x)}{1+\cos(x)}$

Square:

$\displaystyle \csc^2(x)-2\csc(x)\cot(x)+\cot^2(x)=\frac{1-\cos(x)}{1+\cos(x)}$

Convert csc(x) to 1 / sin(x) and cot(x) to cos(x) / sin(x). Thus:

$\displaystyle \frac{1}{\sin^2(x)}-\frac{2\cos(x)}{\sin^2(x)}+\frac{\cos^2(x)}{\sin^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor out the sin²(x) from the denominator:

$\displaystyle \frac{1}{\sin^2(x)}\left(1-2\cos(x)+\cos^2(x)\right)=\frac{1-\cos(x)}{1+\cos(x)}$

Factor (perfect square trinomial):

$\displaystyle \frac{1}{\sin^2(x)}\left((\cos(x)-1)^2\right)=\frac{1-\cos(x)}{1+\cos(x)}$

Using the Pythagorean Identity, we know that sin²(x) = 1 - cos²(x). Hence:

$\displaystyle \frac{(\cos(x)-1)^2}{1-\cos^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor (difference of two squares):

$\displaystyle \frac{(\cos(x)-1)^2}{(1-\cos(x))(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor out a negative from the first factor in the denominator:

$\displaystyle \frac{(\cos(x)-1)^2}{-(\cos(x)-1)(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}$

Cancel:

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Distribute the negative into the numerator. Therefore:

$\displaystyle \frac{1-\cos(x)}{1+\cos(x)}=\displaystyle \frac{1-\cos(x)}{1+\cos(x)}$

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3 years ago

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mestny [16]

Answer:

(i) Not true for any cases, (ii) True for some cases, (iii) True for some cases, (iv) True for all cases.

Step-by-step explanation:

Now we proceed to check each statement in terms of concepts of function from Analytical Geometry:

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(ii) Two lines that have the same y-intercept intersect at exactly one point.

Conditionally true, two lines that have the same y-intercept intersect at exactly one point if and only if slopes are different. (Answer: True for some cases)

(iii) Two lines that have the same slope do not intersect at any point.

Conditionally true, two lines that have the same slope do not intersect at any point if and only if they share the same y-intercept. (Answer: True for some cases)

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True, two lines that have two different slopes intersects at exactly one point no matter what y-intercepts they have. (Answer: True for all cases)

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3 years ago

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klio [65]

Answer:

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4 years ago

Read 2 more answers

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