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Mekhanik [1.2K]
3 years ago
11

Can someone please help me with this?

Mathematics
1 answer:
Svet_ta [14]3 years ago
3 0
Increasing: (-4,-4)
Decreasing: (4,-2)
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Enter the values to complete the input/output table for the function.
Artist 52 [7]

Given function : 3x−6y=12.

We are given x :  −2     0    4.

We need to find the values of y's for x=-2, x=0 and x=4.

Plugging x=-2 in the given equation, we get

3(-2)−6y=12

-6 - 6y = 12.

Adding 6 on both sides, we get

-6+6 - 6y = 12+6

-6y = 18.

Dividing by -6 on both sides, we get

y= -3.

On the same way, plugging x=0.

3(0)−6y=12

-6y =12.

y=-2.

Plugging x=4,

3(4)−6y=12

12 -6y = 12.

Subtracting 12 on both sides.

12-12 -6y = 12-12

-6y=0

y=0.

Therefore,

<h3>x    −2   0   4</h3><h3>y ​    -3   -2  0</h3>
3 0
3 years ago
Solve this equation. Enter your answer in the box.<br> 13(y+7)=3(y−1).
Fofino [41]

★To Solve :

\rm\blue{13(y+7) = 3(y-1)}

⠀⠀⠀⠀⠀

★SOLUTION :

\rm\red\leadsto{13(y+7) = 3(y-1)}

\rm\red\leadsto{13\times{y}+13\times7= 3\times{y}-3\times1}

\rm\red\leadsto{13y+91=3y-3}

\rm\red\leadsto{13y-3y=-3-91}

\rm\red\leadsto{10y=-94}

\rm\red\leadsto{} y =\dfrac{   { \cancel{-94}}^{ \:-45 } }{   { \cancel{10}}^{ \: 5} }

\rm\red\leadsto{y=}\dfrac{-47}{5}

____________________

5 0
3 years ago
Read 2 more answers
Ursula bought 9 dozen rolls of first aid tape for the health office. The rolls were divide equally into 4 boxes. How many rolls
vredina [299]
We know that 12 equals one dozen. It is not asking for a dozen, but for 9 dozen. So, we need to multiply 9 by 12. 9*12 = 108. 

It says the rolls of first aid tape were divided equally into 4 boxes. We need to divide these 108 rolls into 4 equal groups, since that is what took place in the problem. So, we divide 108 by 4. 
108/4 = 27. There are 27 rolls in each box. 
4 0
3 years ago
WORTH 10 points.
Tanya [424]
The answer is B because I did the math
8 0
3 years ago
For f(x)= x+5 and g(x)=4x+2 <br> find (fog)(x) And (gof)(x)
Svetllana [295]

Composing functions means that the input of the outer functions is the output of the inner function.

In fact, you can rewrite the circle notation as

(f\circ g)(x)=f(g(x)),\quad (g\circ f)(x)=g(f(x))

So, we can substitute g(x) with its expression:

(f\circ g)(x)=f(g(x))=f(4x+2)

And since f(x)=x+5, we simply have to add 5 to its input:

f(4x+2)=(4x+2)+5=4x+7

Similarly, we have, substituting f with its expression,

(g\circ f)(x)=g(f(x))=g(x+5)

And since g(x)=4x+2, we have to multiply the input by 4 and add 2:

g(x+5)=4(x+5)+2=4x+20+2=4x+22

7 0
3 years ago
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